Graph 8x+40=0

$8 x + 40 = 0$

Step 1

Solve for $y$ .

Subtract $40$ from both sides of the equation.

$8 x = - 40$

Divide each term in $8 x = - 40$ by $8$ and simplify.

Divide each term in $8 x = - 40$ by $8$ .

$\frac{8 x}{8} = \frac{- 40}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 x}{8} = \frac{- 40}{8}$

Divide $x$ by $1$ .

$x = \frac{- 40}{8}$

Simplify the right side.

Divide $- 40$ by $8$ .

$x = - 5$

Step 2

Since $x = - 5$ is a vertical line, there is no y-intercept and the slope is undefined.

Slope: Undefined

y-intercept: No y-intercept

Step 3

Find two points on the line.

$\begin{array}{c} x & y \\ - 5 & 0 \\ - 5 & 1 \end{array}$

Step 4

Graph the line using the slope, y-intercept, and two points.

Slope: Undefined

y-intercept: No y-intercept

$\begin{array}{c} x & y \\ - 5 & 0 \\ - 5 & 1 \end{array}$

Step 5