Graph 8x-4y=-8

$8 x - 4 y = - 8$

Step 1

Solve for $y$ .

Subtract $8 x$ from both sides of the equation.

$- 4 y = - 8 - 8 x$

Divide each term in $- 4 y = - 8 - 8 x$ by $- 4$ and simplify.

Divide each term in $- 4 y = - 8 - 8 x$ by $- 4$ .

$\frac{- 4 y}{- 4} = \frac{- 8}{- 4} + \frac{- 8 x}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 y}{- 4} = \frac{- 8}{- 4} + \frac{- 8 x}{- 4}$

Divide $y$ by $1$ .

$y = \frac{- 8}{- 4} + \frac{- 8 x}{- 4}$

Simplify the right side.

Simplify each term.

Divide $- 8$ by $- 4$ .

$y = 2 + \frac{- 8 x}{- 4}$

Cancel the common factor of $- 8$ and $- 4$ .

Factor $- 4$ out of $- 8 x$ .

$y = 2 + \frac{- 4 (2 x)}{- 4}$

Cancel the common factors.

Factor $- 4$ out of $- 4$ .

$y = 2 + \frac{- 4 (2 x)}{- 4 (1)}$

Cancel the common factor.

$y = 2 + \frac{- 4 (2 x)}{- 4 \cdot 1}$

Rewrite the expression.

$y = 2 + \frac{2 x}{1}$

Divide $2 x$ by $1$ .

$y = 2 + 2 x$

Step 2

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Reorder $2$ and $2 x$ .

$y = 2 x + 2$

Step 3

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 2$

$b = 2$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $2$

y-intercept: $(0, 2)$

Slope: $2$

y-intercept: $(0, 2)$

Step 4

Any line can be graphed using two points. Select two $x$ values, and plug them into the equation to find the corresponding $y$ values.

Reorder $2$ and $2 x$ .

$y = 2 x + 2$

Create a table of the $x$ and $y$ values.

$\begin{array}{c} x & y \\ 0 & 2 \\ 1 & 4 \end{array}$

Step 5

Graph the line using the slope and the y-intercept, or the points.

Slope: $2$

y-intercept: $(0, 2)$

$\begin{array}{c} x & y \\ 0 & 2 \\ 1 & 4 \end{array}$

Step 6

Graph 8x-4y=-8

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