Graph f^-1(x)=x^3-1

$f^{- 1} (x) = x^{3} - 1$

Step 1

Find the point at $x = - 2$ .

Replace the variable $x$ with $- 2$ in the expression.

$f (- 2) = {(- 2)}^{3} - 1$

Simplify the result.

Raise $- 2$ to the power of $3$ .

$f (- 2) = - 8 - 1$

Subtract $1$ from $- 8$ .

$f (- 2) = - 9$

The final answer is $- 9$ .

$- 9$

Convert $- 9$ to decimal.

$y = - 9$

Step 2

Find the point at $x = - 1$ .

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = {(- 1)}^{3} - 1$

Simplify the result.

Raise $- 1$ to the power of $3$ .

$f (- 1) = - 1 - 1$

Subtract $1$ from $- 1$ .

$f (- 1) = - 2$

The final answer is $- 2$ .

$- 2$

Convert $- 2$ to decimal.

$y = - 2$

Step 3

Find the point at $x = 0$ .

Replace the variable $x$ with $0$ in the expression.

$f (0) = {(0)}^{3} - 1$

Simplify the result.

Raising $0$ to any positive power yields $0$ .

$f (0) = 0 - 1$

Subtract $1$ from $0$ .

$f (0) = - 1$

The final answer is $- 1$ .

$- 1$

Convert $- 1$ to decimal.

$y = - 1$

Step 4

Find the point at $x = 1$ .

Replace the variable $x$ with $1$ in the expression.

$f (1) = {(1)}^{3} - 1$

Simplify the result.

One to any power is one.

$f (1) = 1 - 1$

Subtract $1$ from $1$ .

$f (1) = 0$

The final answer is $0$ .

$0$

Convert $0$ to decimal.

$y = 0$

Step 5

Find the point at $x = 2$ .

Replace the variable $x$ with $2$ in the expression.

$f (2) = {(2)}^{3} - 1$

Simplify the result.

Raise $2$ to the power of $3$ .

$f (2) = 8 - 1$

Subtract $1$ from $8$ .

$f (2) = 7$

The final answer is $7$ .

$7$

Convert $7$ to decimal.

$y = 7$

Step 6

The cubic function can be graphed using the function behavior and the points.

$\begin{array}{c} x & y \\ - 2 & - 9 \\ - 1 & - 2 \\ 0 & - 1 \\ 1 & 0 \\ 2 & 7 \end{array}$

Step 7

The cubic function can be graphed using the function behavior and the selected points.

Falls to the left and rises to the right

$\begin{array}{c} x & y \\ - 2 & - 9 \\ - 1 & - 2 \\ 0 & - 1 \\ 1 & 0 \\ 2 & 7 \end{array}$

Step 8

Graph f^-1(x)=x^3-1

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