Graph -f(2(x-2))+1

Subtract ${\displaystyle 1}$ from both sides of the equation.

Factor ${\displaystyle 2y}$ out of ${\displaystyle -2yx+4y}$.

Rewrite ${\displaystyle -1x}$ as ${\displaystyle -x}$.

Divide each term in ${\displaystyle 2y(-x+2)=-1}$ by ${\displaystyle 2(-x+2)}$ and simplify.

Find where the expression ${\displaystyle \frac{1}{2(x-2)}}$ is undefined.

Consider the rational function ${\displaystyle R\left(x\right)=\frac{a{x}^n}{b{x}^m}}$ where ${\displaystyle n}$ is the degree of the numerator and ${\displaystyle m}$ is the degree of the denominator.

1. If ${\displaystyle n<m}$, then the x-axis, ${\displaystyle y=0}$, is the horizontal asymptote.

2. If ${\displaystyle n=m}$, then the horizontal asymptote is the line ${\displaystyle y=\frac{a}{b}}$.

3. If ${\displaystyle n>m}$, then there is no horizontal asymptote (there is an oblique asymptote).

Find ${\displaystyle n}$ and ${\displaystyle m}$.

Since ${\displaystyle n<m}$, the x-axis, ${\displaystyle y=0}$, is the horizontal asymptote.

There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.

No Oblique Asymptotes

This is the set of all asymptotes.

Vertical Asymptotes: ${\displaystyle x=2}$

Horizontal Asymptotes: ${\displaystyle y=0}$

No Oblique Asymptotes