Graph f(x)=-3*sin(4/3x)

$f (x) = - 3 \cdot \sin (\frac{4}{3} x)$

Use the form $a \sin (b x - c) + d$ to find the variables used to find the amplitude, period, phase shift, and vertical shift.

$a = - 3$

$b = \frac{4}{3}$

$c = 0$

$d = 0$

Find the amplitude $| a |$ .

Amplitude: $3$

Find the period of $- 3 \sin (\frac{4 x}{3})$ .

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Replace $b$ with $\frac{4}{3}$ in the formula for period.

$\frac{2 π}{| \frac{4}{3} |}$

$\frac{4}{3}$ is approximately $1.\overline{3}$ which is positive so remove the absolute value

$\frac{2 π}{\frac{4}{3}}$

Multiply the numerator by the reciprocal of the denominator.

$2 π \frac{3}{4}$

Cancel the common factor of $2$ .

Factor $2$ out of $2 π$ .

$2 (π) \frac{3}{4}$

Factor $2$ out of $4$ .

$2 (π) \frac{3}{2 (2)}$

Cancel the common factor.

$2 π \frac{3}{2 \cdot 2}$

Rewrite the expression.

$π \frac{3}{2}$

Combine $π$ and $\frac{3}{2}$ .

$\frac{π \cdot 3}{2}$

Move $3$ to the left of $π$ .

$\frac{3 π}{2}$

Find the phase shift using the formula $\frac{c}{b}$ .

The phase shift of the function can be calculated from $\frac{c}{b}$ .

Phase Shift: $\frac{c}{b}$

Replace the values of $c$ and $b$ in the equation for phase shift.

Phase Shift: $\frac{0}{\frac{4}{3}}$

Multiply the numerator by the reciprocal of the denominator.

Phase Shift: $0 (\frac{3}{4})$

Multiply $0$ by $\frac{3}{4}$ .

Phase Shift: $0$

List the properties of the trigonometric function.

Amplitude: $3$

Period: $\frac{3 π}{2}$

Phase Shift: None

Vertical Shift: None

Select a few points to graph.

Find the point at $x = 0$ .

Replace the variable $x$ with $0$ in the expression.

$f (0) = - 3 \sin (\frac{4 (0)}{3})$

Simplify the result.

Cancel the common factor of $0$ and $3$ .

Factor $3$ out of $4 (0)$ .

$f (0) = - 3 \sin (\frac{3 (4 \cdot (0))}{3})$

Cancel the common factors.

Factor $3$ out of $3$ .

$f (0) = - 3 \sin (\frac{3 (4 \cdot (0))}{3 (1)})$

Cancel the common factor.

$f (0) = - 3 \sin (\frac{3 (4 \cdot (0))}{3 \cdot 1})$

Rewrite the expression.

$f (0) = - 3 \sin (\frac{4 \cdot (0)}{1})$

Divide $4 \cdot (0)$ by $1$ .

$f (0) = - 3 \sin (4 \cdot (0))$

Multiply $4$ by $0$ .

$f (0) = - 3 \sin (0)$

The exact value of $\sin (0)$ is $0$ .

$f (0) = - 3 \cdot 0$

Multiply $- 3$ by $0$ .

$f (0) = 0$

The final answer is $0$ .

$0$

Find the point at $x = \frac{3 π}{8}$ .

Replace the variable $x$ with $\frac{3 π}{8}$ in the expression.

$f (\frac{3 π}{8}) = - 3 \sin (\frac{4 (\frac{3 π}{8})}{3})$

Simplify the result.

Combine $4$ and $\frac{3 π}{8}$ .

$f (\frac{3 π}{8}) = - 3 \sin (\frac{\frac{4 (3 π)}{8}}{3})$

Multiply $4$ by $3$ .

$f (\frac{3 π}{8}) = - 3 \sin (\frac{\frac{12 π}{8}}{3})$

Reduce the expression $\frac{12 π}{8}$ by cancelling the common factors.

Factor $4$ out of $12 π$ .

$f (\frac{3 π}{8}) = - 3 \sin (\frac{\frac{4 (3 π)}{8}}{3})$

Factor $4$ out of $8$ .

$f (\frac{3 π}{8}) = - 3 \sin (\frac{\frac{4 (3 π)}{4 (2)}}{3})$

Cancel the common factor.

$f (\frac{3 π}{8}) = - 3 \sin (\frac{\frac{4 (3 π)}{4 \cdot 2}}{3})$

Rewrite the expression.

$f (\frac{3 π}{8}) = - 3 \sin (\frac{\frac{3 π}{2}}{3})$

Multiply the numerator by the reciprocal of the denominator.

$f (\frac{3 π}{8}) = - 3 \sin (\frac{3 π}{2} \cdot \frac{1}{3})$

Cancel the common factor of $3$ .

Factor $3$ out of $3 π$ .

$f (\frac{3 π}{8}) = - 3 \sin (\frac{3 (π)}{2} \cdot \frac{1}{3})$

Cancel the common factor.

$f (\frac{3 π}{8}) = - 3 \sin (\frac{3 π}{2} \cdot \frac{1}{3})$

Rewrite the expression.

$f (\frac{3 π}{8}) = - 3 \sin (\frac{π}{2})$

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$f (\frac{3 π}{8}) = - 3 \cdot 1$

Multiply $- 3$ by $1$ .

$f (\frac{3 π}{8}) = - 3$

The final answer is $- 3$ .

$- 3$

Find the point at $x = \frac{3 π}{4}$ .

Replace the variable $x$ with $\frac{3 π}{4}$ in the expression.

$f (\frac{3 π}{4}) = - 3 \sin (\frac{4 (\frac{3 π}{4})}{3})$

Simplify the result.

Combine $4$ and $\frac{3 π}{4}$ .

$f (\frac{3 π}{4}) = - 3 \sin (\frac{\frac{4 (3 π)}{4}}{3})$

Multiply $4$ by $3$ .

$f (\frac{3 π}{4}) = - 3 \sin (\frac{\frac{12 π}{4}}{3})$

Reduce the expression by cancelling the common factors.

Reduce the expression $\frac{12 π}{4}$ by cancelling the common factors.

Factor $4$ out of $12 π$ .

$f (\frac{3 π}{4}) = - 3 \sin (\frac{\frac{4 (3 π)}{4}}{3})$

Factor $4$ out of $4$ .

$f (\frac{3 π}{4}) = - 3 \sin (\frac{\frac{4 (3 π)}{4 (1)}}{3})$

Cancel the common factor.

$f (\frac{3 π}{4}) = - 3 \sin (\frac{\frac{4 (3 π)}{4 \cdot 1}}{3})$

Rewrite the expression.

$f (\frac{3 π}{4}) = - 3 \sin (\frac{\frac{3 π}{1}}{3})$

Divide $3 π$ by $1$ .

$f (\frac{3 π}{4}) = - 3 \sin (\frac{3 π}{3})$

Cancel the common factor of $3$ .

Cancel the common factor.

$f (\frac{3 π}{4}) = - 3 \sin (\frac{3 π}{3})$

Divide $π$ by $1$ .

$f (\frac{3 π}{4}) = - 3 \sin (π)$

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant.

$f (\frac{3 π}{4}) = - 3 \sin (0)$

The exact value of $\sin (0)$ is $0$ .

$f (\frac{3 π}{4}) = - 3 \cdot 0$

Multiply $- 3$ by $0$ .

$f (\frac{3 π}{4}) = 0$

The final answer is $0$ .

$0$

Find the point at $x = \frac{9 π}{8}$ .

Replace the variable $x$ with $\frac{9 π}{8}$ in the expression.

$f (\frac{9 π}{8}) = - 3 \sin (\frac{4 (\frac{9 π}{8})}{3})$

Simplify the result.

Combine $4$ and $\frac{9 π}{8}$ .

$f (\frac{9 π}{8}) = - 3 \sin (\frac{\frac{4 (9 π)}{8}}{3})$

Multiply $4$ by $9$ .

$f (\frac{9 π}{8}) = - 3 \sin (\frac{\frac{36 π}{8}}{3})$

Reduce the expression $\frac{36 π}{8}$ by cancelling the common factors.

Factor $4$ out of $36 π$ .

$f (\frac{9 π}{8}) = - 3 \sin (\frac{\frac{4 (9 π)}{8}}{3})$

Factor $4$ out of $8$ .

$f (\frac{9 π}{8}) = - 3 \sin (\frac{\frac{4 (9 π)}{4 (2)}}{3})$

Cancel the common factor.

$f (\frac{9 π}{8}) = - 3 \sin (\frac{\frac{4 (9 π)}{4 \cdot 2}}{3})$

Rewrite the expression.

$f (\frac{9 π}{8}) = - 3 \sin (\frac{\frac{9 π}{2}}{3})$

Multiply the numerator by the reciprocal of the denominator.

$f (\frac{9 π}{8}) = - 3 \sin (\frac{9 π}{2} \cdot \frac{1}{3})$

Cancel the common factor of $3$ .

Factor $3$ out of $9 π$ .

$f (\frac{9 π}{8}) = - 3 \sin (\frac{3 (3 π)}{2} \cdot \frac{1}{3})$

Cancel the common factor.

$f (\frac{9 π}{8}) = - 3 \sin (\frac{3 (3 π)}{2} \cdot \frac{1}{3})$

Rewrite the expression.

$f (\frac{9 π}{8}) = - 3 \sin (\frac{3 π}{2})$

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because sine is negative in the fourth quadrant.

$f (\frac{9 π}{8}) = - 3 (- \sin (\frac{π}{2}))$

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$f (\frac{9 π}{8}) = - 3 (- 1 \cdot 1)$

Multiply $- 1$ by $1$ .

$f (\frac{9 π}{8}) = - 3 \cdot - 1$

Multiply $- 3$ by $- 1$ .

$f (\frac{9 π}{8}) = 3$

The final answer is $3$ .

$3$

Find the point at $x = \frac{3 π}{2}$ .

Replace the variable $x$ with $\frac{3 π}{2}$ in the expression.

$f (\frac{3 π}{2}) = - 3 \sin (\frac{4 (\frac{3 π}{2})}{3})$

Simplify the result.

Combine $4$ and $\frac{3 π}{2}$ .

$f (\frac{3 π}{2}) = - 3 \sin (\frac{\frac{4 (3 π)}{2}}{3})$

Multiply $4$ by $3$ .

$f (\frac{3 π}{2}) = - 3 \sin (\frac{\frac{12 π}{2}}{3})$

Reduce the expression by cancelling the common factors.

Reduce the expression $\frac{12 π}{2}$ by cancelling the common factors.

Factor $2$ out of $12 π$ .

$f (\frac{3 π}{2}) = - 3 \sin (\frac{\frac{2 (6 π)}{2}}{3})$

Factor $2$ out of $2$ .

$f (\frac{3 π}{2}) = - 3 \sin (\frac{\frac{2 (6 π)}{2 (1)}}{3})$

Cancel the common factor.

$f (\frac{3 π}{2}) = - 3 \sin (\frac{\frac{2 (6 π)}{2 \cdot 1}}{3})$

Rewrite the expression.

$f (\frac{3 π}{2}) = - 3 \sin (\frac{\frac{6 π}{1}}{3})$

Divide $6 π$ by $1$ .

$f (\frac{3 π}{2}) = - 3 \sin (\frac{6 π}{3})$

Cancel the common factor of $6$ and $3$ .

Factor $3$ out of $6 π$ .

$f (\frac{3 π}{2}) = - 3 \sin (\frac{3 (2 π)}{3})$

Cancel the common factors.

Factor $3$ out of $3$ .

$f (\frac{3 π}{2}) = - 3 \sin (\frac{3 (2 π)}{3 (1)})$

Cancel the common factor.

$f (\frac{3 π}{2}) = - 3 \sin (\frac{3 (2 π)}{3 \cdot 1})$

Rewrite the expression.

$f (\frac{3 π}{2}) = - 3 \sin (\frac{2 π}{1})$

Divide $2 π$ by $1$ .

$f (\frac{3 π}{2}) = - 3 \sin (2 π)$

Subtract full rotations of $2 π$ until the angle is greater than or equal to $0$ and less than $2 π$ .

$f (\frac{3 π}{2}) = - 3 \sin (0)$

The exact value of $\sin (0)$ is $0$ .

$f (\frac{3 π}{2}) = - 3 \cdot 0$

Multiply $- 3$ by $0$ .

$f (\frac{3 π}{2}) = 0$

The final answer is $0$ .

$0$

List the points in a table.

$\begin{array}{c} x & f (x) \\ 0 & 0 \\ \frac{3 π}{8} & - 3 \\ \frac{3 π}{4} & 0 \\ \frac{9 π}{8} & 3 \\ \frac{3 π}{2} & 0 \end{array}$

The trig function can be graphed using the amplitude, period, phase shift, vertical shift, and the points.

Amplitude: $3$

Period: $\frac{3 π}{2}$

Phase Shift: None

Vertical Shift: None

$\begin{array}{c} x & f (x) \\ 0 & 0 \\ \frac{3 π}{8} & - 3 \\ \frac{3 π}{4} & 0 \\ \frac{9 π}{8} & 3 \\ \frac{3 π}{2} & 0 \end{array}$

Graph f(x)=-3*sin(4/3x)

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