Graph f(x) = log of 2x

$f (x) = \log (2 x)$

Step 1

Find the asymptotes.

Set the argument of the logarithm equal to zero.

$2 x = 0$

Divide each term in $2 x = 0$ by $2$ and simplify.

Divide each term in $2 x = 0$ by $2$ .

$\frac{2 x}{2} = \frac{0}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{0}{2}$

Divide $x$ by $1$ .

$x = \frac{0}{2}$

Simplify the right side.

Divide $0$ by $2$ .

$x = 0$

The vertical asymptote occurs at $x = 0$ .

Vertical Asymptote: $x = 0$

Step 2

Find the point at $x = 5$ .

Replace the variable $x$ with $5$ in the expression.

$f (5) = \log (2 (5))$

Simplify the result.

Multiply $2$ by $5$ .

$f (5) = \log (10)$

Logarithm base $10$ of $10$ is $1$ .

$f (5) = 1$

The final answer is $1$ .

$1$

Convert $1$ to decimal.

$y = 1$

Step 3

Find the point at $x = 1$ .

Replace the variable $x$ with $1$ in the expression.

$f (1) = \log (2 (1))$

Simplify the result.

Multiply $2$ by $1$ .

$f (1) = \log (2)$

The final answer is $\log (2)$ .

$\log (2)$

Convert $\log (2)$ to decimal.

$y = 0.30102999$

Step 4

Find the point at $x = 2$ .

Replace the variable $x$ with $2$ in the expression.

$f (2) = \log (2 (2))$

Simplify the result.

Multiply $2$ by $2$ .

$f (2) = \log (4)$

The final answer is $\log (4)$ .

$\log (4)$

Convert $\log (4)$ to decimal.

$y = 0.60205999$

Step 5

The log function can be graphed using the vertical asymptote at $x = 0$ and the points $(5, 1), (1, 0.30102999), (2, 0.60205999)$ .

Vertical Asymptote: $x = 0$

$\begin{array}{c} x & y \\ 1 & 0.301 \\ 2 & 0.602 \\ 5 & 1 \end{array}$

Step 6

Graph f(x) = log of 2x

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