Graph F(x)=(q(x))/(x^2+12x+36)

$F (x) = \frac{q (x)}{x^{2} + 12 x + 36}$

Find the standard form of the hyperbola.

Move all terms containing variables to the left side of the equation.

Subtract $\frac{q (x)}{x^{2} + 12 x + 36}$ from both sides of the equation.

$y - \frac{q (x)}{x^{2} + 12 x + 36} = 0$

Factor using the perfect square rule.

Rewrite $36$ as $6^{2}$ .

$y - \frac{q x}{x^{2} + 12 x + 6^{2}} = 0$

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$12 x = 2 \cdot x \cdot 6$

Rewrite the polynomial.

$y - \frac{q x}{x^{2} + 2 \cdot x \cdot 6 + 6^{2}} = 0$

Factor using the perfect square trinomial rule $a^{2} + 2 a b + b^{2} = {(a + b)}^{2}$ , where $a = x$ and $b = 6$ .

$y - \frac{q x}{{(x + 6)}^{2}} = 0$

Reorder $y$ and $- \frac{q x}{{(x + 6)}^{2}}$ .

$- \frac{q x}{{(x + 6)}^{2}} + y = 0$

Divide each term by $0$ to make the right side equal to one.

$- \frac{\frac{q x}{{(x + 6)}^{2}}}{0} + \frac{y}{0} = \frac{0}{0}$

Simplify each term in the equation in order to set the right side equal to $1$ . The standard form of an ellipse or hyperbola requires the right side of the equation be $1$ .

$y - q x = 1$

This is the form of a hyperbola. Use this form to determine the values used to find vertices and asymptotes of the hyperbola.

$\frac{{(x - h)}^{2}}{a^{2}} - \frac{{(y - k)}^{2}}{b^{2}} = 1$

Match the values in this hyperbola to those of the standard form. The variable $h$ represents the x-offset from the origin, $k$ represents the y-offset from origin, $a$ .

$a = 1$

$b = 1$

$k = 0$

$h = 0$

The center of a hyperbola follows the form of $(h, k)$ . Substitute in the values of $h$ and $k$ .

$(0, 0)$

Find $c$ , the distance from the center to a focus.

Find the distance from the center to a focus of the hyperbola by using the following formula.

$\sqrt{a^{2} + b^{2}}$

Substitute the values of $a$ and $b$ in the formula.

$\sqrt{{(1)}^{2} + {(1)}^{2}}$

Simplify.

One to any power is one.

$\sqrt{1 + {(1)}^{2}}$

One to any power is one.

$\sqrt{1 + 1}$

Add $1$ and $1$ .

$\sqrt{2}$

Find the vertices.

The first vertex of a hyperbola can be found by adding $a$ to $h$ .

$(h + a, k)$

Substitute the known values of $h$ , $a$ , and $k$ into the formula and simplify.

$(1, 0)$

The second vertex of a hyperbola can be found by subtracting $a$ from $h$ .

$(h - a, k)$

Substitute the known values of $h$ , $a$ , and $k$ into the formula and simplify.

$(- 1, 0)$

The vertices of a hyperbola follow the form of $(h \pm a, k)$ . Hyperbolas have two vertices.

$(1, 0), (- 1, 0)$

Find the foci.

The first focus of a hyperbola can be found by adding $c$ to $h$ .

$(h + c, k)$

Substitute the known values of $h$ , $c$ , and $k$ into the formula and simplify.

$(\sqrt{2}, 0)$

The second focus of a hyperbola can be found by subtracting $c$ from $h$ .

$(h - c, k)$

Substitute the known values of $h$ , $c$ , and $k$ into the formula and simplify.

$(- \sqrt{2}, 0)$

The foci of a hyperbola follow the form of $(h \pm \sqrt{a^{2} + b^{2}}, k)$ . Hyperbolas have two foci.

$(\sqrt{2}, 0), (- \sqrt{2}, 0)$

Find the eccentricity.

Find the eccentricity by using the following formula.

$\frac{\sqrt{a^{2} + b^{2}}}{a}$

Substitute the values of $a$ and $b$ into the formula.

$\frac{\sqrt{{(1)}^{2} + {(1)}^{2}}}{1}$

Simplify.

Divide $\sqrt{{(1)}^{2} + {(1)}^{2}}$ by $1$ .

$\sqrt{{(1)}^{2} + {(1)}^{2}}$

One to any power is one.

$\sqrt{1 + {(1)}^{2}}$

One to any power is one.

$\sqrt{1 + 1}$

Add $1$ and $1$ .

$\sqrt{2}$

Find the focal parameter.

Find the value of the focal parameter of the hyperbola by using the following formula.

$\frac{b^{2}}{\sqrt{a^{2} + b^{2}}}$

Substitute the values of $b$ and $\sqrt{a^{2} + b^{2}}$ in the formula.

$\frac{1^{2}}{\sqrt{2}}$

Simplify.

One to any power is one.

$\frac{1}{\sqrt{2}}$

Multiply $\frac{1}{\sqrt{2}}$ by $\frac{\sqrt{2}}{\sqrt{2}}$ .

$\frac{1}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}}$

Combine and simplify the denominator.

Multiply $\frac{1}{\sqrt{2}}$ by $\frac{\sqrt{2}}{\sqrt{2}}$ .

$\frac{\sqrt{2}}{\sqrt{2} \sqrt{2}}$

Raise $\sqrt{2}$ to the power of $1$ .

$\frac{\sqrt{2}}{{\sqrt{2}}^{1} \sqrt{2}}$

Raise $\sqrt{2}$ to the power of $1$ .

$\frac{\sqrt{2}}{{\sqrt{2}}^{1} {\sqrt{2}}^{1}}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{\sqrt{2}}{{\sqrt{2}}^{1 + 1}}$

Add $1$ and $1$ .

$\frac{\sqrt{2}}{{\sqrt{2}}^{2}}$

Rewrite ${\sqrt{2}}^{2}$ as $2$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$\frac{\sqrt{2}}{{(2^{\frac{1}{2}})}^{2}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{\sqrt{2}}{2^{\frac{1}{2} \cdot 2}}$

Combine $\frac{1}{2}$ and $2$ .

$\frac{\sqrt{2}}{2^{\frac{2}{2}}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{\sqrt{2}}{2^{\frac{2}{2}}}$

Rewrite the expression.

$\frac{\sqrt{2}}{2^{1}}$

Evaluate the exponent.

$\frac{\sqrt{2}}{2}$

The asymptotes follow the form $y = \pm \frac{b (x - h)}{a} + k$ because this hyperbola opens left and right.

$y = \pm 1 \cdot x + 0$

Simplify $1 \cdot x + 0$ .

Add $1 \cdot x$ and $0$ .

$y = 1 \cdot x$

Multiply $x$ by $1$ .

$y = x$

Simplify $- 1 \cdot x + 0$ .

Add $- 1 \cdot x$ and $0$ .

$y = - 1 \cdot x$

Rewrite $- 1 x$ as $- x$ .

$y = - x$

This hyperbola has two asymptotes.

$y = x, y = - x$

These values represent the important values for graphing and analyzing a hyperbola.

Center: $(0, 0)$

Vertices: $(1, 0), (- 1, 0)$

Foci: $(\sqrt{2}, 0), (- \sqrt{2}, 0)$

Eccentricity: $\sqrt{2}$

Focal Parameter: $\frac{\sqrt{2}}{2}$

Asymptotes: $y = x$ , $y = - x$

Graph F(x)=(q(x))/(x^2+12x+36)

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