Graph f(x)=-x^3

$f (x) = - x^{3}$

Step 1

Find the point at $x = - 2$ .

Replace the variable $x$ with $- 2$ in the expression.

$f (- 2) = - {(- 2)}^{3}$

Simplify the result.

Raise $- 2$ to the power of $3$ .

$f (- 2) = 8$

The final answer is $8$ .

$8$

Convert $8$ to decimal.

$y = 8$

Step 2

Find the point at $x = - 1$ .

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = - {(- 1)}^{3}$

Simplify the result.

Multiply $- 1$ by ${(- 1)}^{3}$ by adding the exponents.

Multiply $- 1$ by ${(- 1)}^{3}$ .

Raise $- 1$ to the power of $1$ .

$f (- 1) = (- 1) {(- 1)}^{3}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f (- 1) = {(- 1)}^{1 + 3}$

Add $1$ and $3$ .

$f (- 1) = {(- 1)}^{4}$

Raise $- 1$ to the power of $4$ .

$f (- 1) = 1$

The final answer is $1$ .

$1$

Convert $1$ to decimal.

$y = 1$

Step 3

Find the point at $x = 0$ .

Replace the variable $x$ with $0$ in the expression.

$f (0) = - {(0)}^{3}$

Simplify the result.

Raising $0$ to any positive power yields $0$ .

$f (0) = - 0$

Multiply $- 1$ by $0$ .

$f (0) = 0$

The final answer is $0$ .

$0$

Convert $0$ to decimal.

$y = 0$

Step 4

Find the point at $x = 1$ .

Replace the variable $x$ with $1$ in the expression.

$f (1) = - {(1)}^{3}$

Simplify the result.

One to any power is one.

$f (1) = - 1 \cdot 1$

Multiply $- 1$ by $1$ .

$f (1) = - 1$

The final answer is $- 1$ .

$- 1$

Convert $- 1$ to decimal.

$y = - 1$

Step 5

Find the point at $x = 2$ .

Replace the variable $x$ with $2$ in the expression.

$f (2) = - {(2)}^{3}$

Simplify the result.

Raise $2$ to the power of $3$ .

$f (2) = - 1 \cdot 8$

Multiply $- 1$ by $8$ .

$f (2) = - 8$

The final answer is $- 8$ .

$- 8$

Convert $- 8$ to decimal.

$y = - 8$

Step 6

The cubic function can be graphed using the function behavior and the points.

$\begin{array}{c} x & y \\ - 2 & 8 \\ - 1 & 1 \\ 0 & 0 \\ 1 & - 1 \\ 2 & - 8 \end{array}$

Step 7

The cubic function can be graphed using the function behavior and the selected points.

Rises to the left and falls to the right

$\begin{array}{c} x & y \\ - 2 & 8 \\ - 1 & 1 \\ 0 & 0 \\ 1 & - 1 \\ 2 & - 8 \end{array}$

Step 8

Graph f(x)=-x^3

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