Graph f(x)=(x-3)^2-2

$f (x) = {(x - 3)}^{2} - 2$

Step 1

Find the properties of the given parabola.

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = 1$

$h = 3$

$k = - 2$

Since the value of $a$ is positive, the parabola opens up.

Opens Up

Find the vertex $(h, k)$ .

$(3, - 2)$

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot 1}$

Cancel the common factor of $1$ .

Cancel the common factor.

$\frac{1}{4 \cdot 1}$

Rewrite the expression.

$\frac{1}{4}$

Find the focus.

The focus of a parabola can be found by adding $p$ to the y-coordinate $k$ if the parabola opens up or down.

$(h, k + p)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(3, - \frac{7}{4})$

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$x = 3$

Find the directrix.

The directrix of a parabola is the horizontal line found by subtracting $p$ from the y-coordinate $k$ of the vertex if the parabola opens up or down.

$y = k - p$

Substitute the known values of $p$ and $k$ into the formula and simplify.

$y = - \frac{9}{4}$

Use the properties of the parabola to analyze and graph the parabola.

Direction: Opens Up

Vertex: $(3, - 2)$

Focus: $(3, - \frac{7}{4})$

Axis of Symmetry: $x = 3$

Directrix: $y = - \frac{9}{4}$

Direction: Opens Up

Vertex: $(3, - 2)$

Focus: $(3, - \frac{7}{4})$

Axis of Symmetry: $x = 3$

Directrix: $y = - \frac{9}{4}$

Step 2

Select a few $x$ values, and plug them into the equation to find the corresponding $y$ values. The $x$ values should be selected around the vertex.

Replace the variable $x$ with $2$ in the expression.

$f (2) = {(2)}^{2} - 6 \cdot 2 + 7$

Simplify the result.

Simplify each term.

Raise $2$ to the power of $2$ .

$f (2) = 4 - 6 \cdot 2 + 7$

Multiply $- 6$ by $2$ .

$f (2) = 4 - 12 + 7$

Simplify by adding and subtracting.

Subtract $12$ from $4$ .

$f (2) = - 8 + 7$

Add $- 8$ and $7$ .

$f (2) = - 1$

The final answer is $- 1$ .

$- 1$

The $y$ value at $x = 2$ is $- 1$ .

$y = - 1$

Replace the variable $x$ with $1$ in the expression.

$f (1) = {(1)}^{2} - 6 \cdot 1 + 7$

Simplify the result.

Simplify each term.

One to any power is one.

$f (1) = 1 - 6 \cdot 1 + 7$

Multiply $- 6$ by $1$ .

$f (1) = 1 - 6 + 7$

Simplify by adding and subtracting.

Subtract $6$ from $1$ .

$f (1) = - 5 + 7$

Add $- 5$ and $7$ .

$f (1) = 2$

The final answer is $2$ .

$2$

The $y$ value at $x = 1$ is $2$ .

$y = 2$

Replace the variable $x$ with $4$ in the expression.

$f (4) = {(4)}^{2} - 6 \cdot 4 + 7$

Simplify the result.

Simplify each term.

Raise $4$ to the power of $2$ .

$f (4) = 16 - 6 \cdot 4 + 7$

Multiply $- 6$ by $4$ .

$f (4) = 16 - 24 + 7$

Simplify by adding and subtracting.

Subtract $24$ from $16$ .

$f (4) = - 8 + 7$

Add $- 8$ and $7$ .

$f (4) = - 1$

The final answer is $- 1$ .

$- 1$

The $y$ value at $x = 4$ is $- 1$ .

$y = - 1$

Replace the variable $x$ with $5$ in the expression.

$f (5) = {(5)}^{2} - 6 \cdot 5 + 7$

Simplify the result.

Simplify each term.

Raise $5$ to the power of $2$ .

$f (5) = 25 - 6 \cdot 5 + 7$

Multiply $- 6$ by $5$ .

$f (5) = 25 - 30 + 7$

Simplify by adding and subtracting.

Subtract $30$ from $25$ .

$f (5) = - 5 + 7$

Add $- 5$ and $7$ .

$f (5) = 2$

The final answer is $2$ .

$2$

The $y$ value at $x = 5$ is $2$ .

$y = 2$

Graph the parabola using its properties and the selected points.

$\begin{array}{c} x & y \\ 1 & 2 \\ 2 & - 1 \\ 3 & - 2 \\ 4 & - 1 \\ 5 & 2 \end{array}$

Step 3

Graph the parabola using its properties and the selected points.

Direction: Opens Up

Vertex: $(3, - 2)$

Focus: $(3, - \frac{7}{4})$

Axis of Symmetry: $x = 3$

Directrix: $y = - \frac{9}{4}$

$\begin{array}{c} x & y \\ 1 & 2 \\ 2 & - 1 \\ 3 & - 2 \\ 4 & - 1 \\ 5 & 2 \end{array}$

Step 4

Graph f(x)=(x-3)^2-2

Related Questions

Support LCMGCF.com by disabling your adblocker.