Graph F(x)=x(x-5)

$F (x) = x (x - 5)$

Find the properties of the given parabola.

Rewrite the equation in vertex form.

Simplify $x (x - 5)$ .

Apply the distributive property.

$y = x \cdot x + x \cdot - 5$

Simplify the expression.

Multiply $x$ by $x$ .

$y = x^{2} + x \cdot - 5$

Move $- 5$ to the left of $x$ .

$y = x^{2} - 5 x$

Complete the square for $x^{2} - 5 x$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = - 5$

$c = 0$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{- 5}{2 \cdot 1}$

Simplify the right side.

Multiply $2$ by $1$ .

$d = \frac{- 5}{2}$

Move the negative in front of the fraction.

$d = - \frac{5}{2}$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{{(- 5)}^{2}}{4 \cdot 1}$

Simplify the right side.

Simplify each term.

Raise $- 5$ to the power of $2$ .

$e = 0 - \frac{25}{4 \cdot 1}$

Multiply $4$ by $1$ .

$e = 0 - \frac{25}{4}$

Subtract $\frac{25}{4}$ from $0$ .

$e = - \frac{25}{4}$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(x - \frac{5}{2})}^{2} - \frac{25}{4}$ .

${(x - \frac{5}{2})}^{2} - \frac{25}{4}$

Set $y$ equal to the new right side.

$y = {(x - \frac{5}{2})}^{2} - \frac{25}{4}$

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = 1$

$h = \frac{5}{2}$

$k = - \frac{25}{4}$

Since the value of $a$ is positive, the parabola opens up.

Opens Up

Find the vertex $(h, k)$ .

$(\frac{5}{2}, - \frac{25}{4})$

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot 1}$

Cancel the common factor of $1$ .

Cancel the common factor.

$\frac{1}{4 \cdot 1}$

Rewrite the expression.

$\frac{1}{4}$

Find the focus.

The focus of a parabola can be found by adding $p$ to the y-coordinate $k$ if the parabola opens up or down.

$(h, k + p)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(\frac{5}{2}, - 6)$

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$x = \frac{5}{2}$

Find the directrix.

The directrix of a parabola is the horizontal line found by subtracting $p$ from the y-coordinate $k$ of the vertex if the parabola opens up or down.

$y = k - p$

Substitute the known values of $p$ and $k$ into the formula and simplify.

$y = - \frac{13}{2}$

Use the properties of the parabola to analyze and graph the parabola.

Direction: Opens Up

Vertex: $(\frac{5}{2}, - \frac{25}{4})$

Focus: $(\frac{5}{2}, - 6)$

Axis of Symmetry: $x = \frac{5}{2}$

Directrix: $y = - \frac{13}{2}$

Direction: Opens Up

Vertex: $(\frac{5}{2}, - \frac{25}{4})$

Focus: $(\frac{5}{2}, - 6)$

Axis of Symmetry: $x = \frac{5}{2}$

Directrix: $y = - \frac{13}{2}$

Select a few $x$ values, and plug them into the equation to find the corresponding $y$ values. The $x$ values should be selected around the vertex.

Replace the variable $x$ with $1$ in the expression.

$f (1) = {(1)}^{2} - 5 \cdot 1$

Simplify the result.

Simplify each term.

One to any power is one.

$f (1) = 1 - 5 \cdot 1$

Multiply $- 5$ by $1$ .

$f (1) = 1 - 5$

Subtract $5$ from $1$ .

$f (1) = - 4$

The final answer is $- 4$ .

$- 4$

The $y$ value at $x = 1$ is $- 4$ .

$y = - 4$

Replace the variable $x$ with $0$ in the expression.

$f (0) = {(0)}^{2} - 5 \cdot 0$

Simplify the result.

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$f (0) = 0 - 5 \cdot 0$

Multiply $- 5$ by $0$ .

$f (0) = 0 + 0$

Add $0$ and $0$ .

$f (0) = 0$

The final answer is $0$ .

$0$

The $y$ value at $x = 0$ is $0$ .

$y = 0$

Replace the variable $x$ with $3$ in the expression.

$f (3) = {(3)}^{2} - 5 \cdot 3$

Simplify the result.

Simplify each term.

Raise $3$ to the power of $2$ .

$f (3) = 9 - 5 \cdot 3$

Multiply $- 5$ by $3$ .

$f (3) = 9 - 15$

Subtract $15$ from $9$ .

$f (3) = - 6$

The final answer is $- 6$ .

$- 6$

The $y$ value at $x = 3$ is $- 6$ .

$y = - 6$

Replace the variable $x$ with $4$ in the expression.

$f (4) = {(4)}^{2} - 5 \cdot 4$

Simplify the result.

Simplify each term.

Raise $4$ to the power of $2$ .

$f (4) = 16 - 5 \cdot 4$

Multiply $- 5$ by $4$ .

$f (4) = 16 - 20$

Subtract $20$ from $16$ .

$f (4) = - 4$

The final answer is $- 4$ .

$- 4$

The $y$ value at $x = 4$ is $- 4$ .

$y = - 4$

Graph the parabola using its properties and the selected points.

$\begin{array}{c} x & y \\ 0 & 0 \\ 1 & - 4 \\ \frac{5}{2} & - \frac{25}{4} \\ 3 & - 6 \\ 4 & - 4 \end{array}$

Graph the parabola using its properties and the selected points.

Direction: Opens Up

Vertex: $(\frac{5}{2}, - \frac{25}{4})$

Focus: $(\frac{5}{2}, - 6)$

Axis of Symmetry: $x = \frac{5}{2}$

Directrix: $y = - \frac{13}{2}$

$\begin{array}{c} x & y \\ 0 & 0 \\ 1 & - 4 \\ \frac{5}{2} & - \frac{25}{4} \\ 3 & - 6 \\ 4 & - 4 \end{array}$

Graph F(x)=x(x-5)

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