Graph g(x)=f(x)+1/3

$g (x) = f (x) + \frac{1}{3}$

Rewrite the function as an equation.

$y = f (x) + \frac{1}{3}$

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 1$

$b = \frac{1}{3}$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $1$

y-intercept: $(0, \frac{1}{3})$

Slope: $1$

y-intercept: $(0, \frac{1}{3})$

Any line can be graphed using two points. Select two $x$ values, and plug them into the equation to find the corresponding $y$ values.

Create a table of the $x$ and $y$ values.

$\begin{array}{c} x & y \\ 0 & \frac{1}{3} \\ 1 & f + \frac{1}{3} \end{array}$

Graph the line using the slope and the y-intercept, or the points.

Slope: $1$

y-intercept: $(0, \frac{1}{3})$

$\begin{array}{c} x & y \\ 0 & \frac{1}{3} \\ 1 & f + \frac{1}{3} \end{array}$