Graph Graph y> = square root of x-2+1

Graph $y \geq \sqrt{x - 2} + 1$

The equation is not linear, so a constant slope does not exist.

Not Linear

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $\sqrt{x - 2} + 1$ .

$y \geq \sqrt{x - 2} + 1$