Graph square root of y

$\sqrt{y}$

Step 1

The domain in terms of $y$ are all the $y$ values that make the radicand non-negative.

$[0, \infty)$

${y | y \geq 0}$

Step 2

To find the radical expression end point, substitute the $y$ value $0$ , which is the least value in the domain, into $f (y) = \sqrt{y}$ .

Replace the variable $y$ with $0$ in the expression.

$f (0) = \sqrt{0}$

Simplify the result.

Remove parentheses.

$f (0) = \sqrt{0}$

Rewrite $0$ as $0^{2}$ .

$f (0) = \sqrt{0^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$f (0) = 0$

The final answer is $0$ .

$0$

Step 3

The radical expression end point is $(0, 0)$ .

$(0, 0)$

Step 4

Select a few $y$ values from the domain. It would be more useful to select the values so that they are next to the $y$ value of the radical expression end point.

Substitute the $y$ value $1$ into $\sqrt{y}$ . In this case, the point is $(1, 1)$ .

Replace the variable $y$ with $1$ in the expression.

$f (1) = \sqrt{1}$

Simplify the result.

Remove parentheses.

$f (1) = \sqrt{1}$

Any root of $1$ is $1$ .

$f (1) = 1$

The final answer is $1$ .

$y = 1$

Substitute the $y$ value $2$ into $\sqrt{y}$ . In this case, the point is $(1.41, 2)$ .

Replace the variable $y$ with $2$ in the expression.

$f (2) = \sqrt{2}$

Simplify the result.

Remove parentheses.

$f (2) = \sqrt{2}$

The final answer is $\sqrt{2}$ .

$y = \sqrt{2}$

The square root can be graphed using the points around the vertex $(0, 0), (1, 1), (1.41, 2)$

$\begin{array}{c} x & y \\ 0 & 0 \\ 1 & 1 \\ 1.41 & 2 \end{array}$

Step 5

Graph square root of y

Related Questions

Support LCMGCF.com by disabling your adblocker.