Graph Using a Table of Values f(x)=1/(x+1)

$f (x) = \frac{1}{x + 1}$

Step 1

Substitute $- 2$ for $x$ and find the result for $y$ .

$y = \frac{1}{(- 2) + 1}$

Step 2

Solve the equation for $y$ .

Remove parentheses.

$y = \frac{1}{- 2 + 1}$

Remove parentheses.

$y = \frac{1}{(- 2) + 1}$

Simplify $\frac{1}{(- 2) + 1}$ .

Add $- 2$ and $1$ .

$y = \frac{1}{- 1}$

Divide $1$ by $- 1$ .

$y = - 1$

Step 3

Substitute $0$ for $x$ and find the result for $y$ .

$y = \frac{1}{(0) + 1}$

Step 4

Solve the equation for $y$ .

Remove parentheses.

$y = \frac{1}{0 + 1}$

Remove parentheses.

$y = \frac{1}{(0) + 1}$

Simplify $\frac{1}{(0) + 1}$ .

Add $0$ and $1$ .

$y = \frac{1}{1}$

Divide $1$ by $1$ .

$y = 1$

Step 5

Substitute $1$ for $x$ and find the result for $y$ .

$y = \frac{1}{(1) + 1}$

Step 6

Solve the equation for $y$ .

Remove parentheses.

$y = \frac{1}{1 + 1}$

Remove parentheses.

$y = \frac{1}{(1) + 1}$

Add $1$ and $1$ .

$y = \frac{1}{2}$

Step 7

Substitute $2$ for $x$ and find the result for $y$ .

$y = \frac{1}{(2) + 1}$

Step 8

Solve the equation for $y$ .

Remove parentheses.

$y = \frac{1}{2 + 1}$

Remove parentheses.

$y = \frac{1}{(2) + 1}$

Add $2$ and $1$ .

$y = \frac{1}{3}$

Step 9

This is a table of possible values to use when graphing the equation.

$\begin{array}{c} x & y \\ - 2 & - 1 \\ 0 & 1 \\ 1 & \frac{1}{2} \\ 2 & \frac{1}{3} \end{array}$

Step 10

Graph Using a Table of Values f(x)=1/(x+1)

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