Graph Using a Table of Values f(x)=2 square root of x+1

$f (x) = 2 \sqrt{x + 1}$

Substitute $- 2$ for $x$ and find the result for $y$ .

$y = 2 \sqrt{(- 2) + 1}$

Simplify $2 \sqrt{(- 2) + 1}$ .

Add $- 2$ and $1$ .

$y = 2 \sqrt{- 1}$

Rewrite $\sqrt{- 1}$ as $i$ .

$y = 2 i$

Substitute $- 1$ for $x$ and find the result for $y$ .

$y = 2 \sqrt{(- 1) + 1}$

Simplify $2 \sqrt{(- 1) + 1}$ .

Add $- 1$ and $1$ .

$y = 2 \sqrt{0}$

Rewrite $0$ as $0^{2}$ .

$y = 2 \sqrt{0^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$y = 2 \cdot 0$

Multiply $2$ by $0$ .

$y = 0$

Substitute $0$ for $x$ and find the result for $y$ .

$y = 2 \sqrt{(0) + 1}$

Simplify $2 \sqrt{(0) + 1}$ .

Add $0$ and $1$ .

$y = 2 \sqrt{1}$

Any root of $1$ is $1$ .

$y = 2 \cdot 1$

Multiply $2$ by $1$ .

$y = 2$

Substitute $1$ for $x$ and find the result for $y$ .

$y = 2 \sqrt{(1) + 1}$

Add $1$ and $1$ .

$y = 2 \sqrt{2}$

Substitute $2$ for $x$ and find the result for $y$ .

$y = 2 \sqrt{(2) + 1}$

Add $2$ and $1$ .

$y = 2 \sqrt{3}$

This is a table of possible values to use when graphing the equation.

$\begin{array}{c} x & y \\ - 2 & 2 i \\ - 1 & 0 \\ 0 & 2 \\ 1 & 2 \sqrt{2} \\ 2 & 2 \sqrt{3} \end{array}$