Graph Using a Table of Values f(x)=(x-1)/(x+1)

$f (x) = \frac{x - 1}{x + 1}$

Step 1

Substitute $- 2$ for $x$ and find the result for $y$ .

$y = \frac{(- 2) - 1}{(- 2) + 1}$

Step 2

Solve the equation for $y$ .

Remove parentheses.

$y = \frac{- 2 - 1}{(- 2) + 1}$

Remove parentheses.

$y = \frac{- 2 - 1}{- 2 + 1}$

Remove parentheses.

$y = \frac{(- 2) - 1}{(- 2) + 1}$

Simplify $\frac{(- 2) - 1}{(- 2) + 1}$ .

Subtract $1$ from $- 2$ .

$y = \frac{- 3}{- 2 + 1}$

Add $- 2$ and $1$ .

$y = \frac{- 3}{- 1}$

Divide $- 3$ by $- 1$ .

$y = 3$

Step 3

Substitute $0$ for $x$ and find the result for $y$ .

$y = \frac{(0) - 1}{(0) + 1}$

Step 4

Solve the equation for $y$ .

Remove parentheses.

$y = \frac{0 - 1}{(0) + 1}$

Remove parentheses.

$y = \frac{0 - 1}{0 + 1}$

Remove parentheses.

$y = \frac{(0) - 1}{(0) + 1}$

Cancel the common factor of $(0) - 1$ and $(0) + 1$ .

Rewrite $0$ as $- 1 (0)$ .

$y = \frac{- 1 (0) - 1}{(0) + 1}$

Rewrite $- 1$ as $- 1 (1)$ .

$y = \frac{- 1 \cdot 0 - 1 \cdot 1}{(0) + 1}$

Factor $- 1$ out of $- 1 \cdot 0 - 1 \cdot 1$ .

$y = \frac{- 1 \cdot (0 + 1)}{(0) + 1}$

Cancel the common factor.

$y = \frac{- 1 \cdot (0 + 1)}{0 + 1}$

Divide $- 1$ by $1$ .

$y = - 1$

Step 5

Substitute $1$ for $x$ and find the result for $y$ .

$y = \frac{(1) - 1}{(1) + 1}$

Step 6

Solve the equation for $y$ .

Remove parentheses.

$y = \frac{1 - 1}{(1) + 1}$

Remove parentheses.

$y = \frac{1 - 1}{1 + 1}$

Remove parentheses.

$y = \frac{(1) - 1}{(1) + 1}$

Simplify $\frac{(1) - 1}{(1) + 1}$ .

Subtract $1$ from $1$ .

$y = \frac{0}{1 + 1}$

Add $1$ and $1$ .

$y = \frac{0}{2}$

Divide $0$ by $2$ .

$y = 0$

Step 7

Substitute $2$ for $x$ and find the result for $y$ .

$y = \frac{(2) - 1}{(2) + 1}$

Step 8

Solve the equation for $y$ .

Remove parentheses.

$y = \frac{2 - 1}{(2) + 1}$

Remove parentheses.

$y = \frac{2 - 1}{2 + 1}$

Remove parentheses.

$y = \frac{(2) - 1}{(2) + 1}$

Simplify $\frac{(2) - 1}{(2) + 1}$ .

Subtract $1$ from $2$ .

$y = \frac{1}{2 + 1}$

Add $2$ and $1$ .

$y = \frac{1}{3}$

Step 9

This is a table of possible values to use when graphing the equation.

$\begin{array}{c} x & y \\ - 2 & 3 \\ 0 & - 1 \\ 1 & 0 \\ 2 & \frac{1}{3} \end{array}$

Step 10

Graph Using a Table of Values f(x)=(x-1)/(x+1)

Related Questions

Support LCMGCF.com by disabling your adblocker.