Graph Using a Table of Values f(x)=(x+3)/(x-2)

$f (x) = \frac{x + 3}{x - 2}$

Substitute $- 2$ for $x$ and find the result for $y$ .

$y = \frac{(- 2) + 3}{(- 2) - 2}$

Solve the equation for $y$ .

Remove parentheses.

$y = \frac{- 2 + 3}{(- 2) - 2}$

Remove parentheses.

$y = \frac{- 2 + 3}{- 2 - 2}$

Remove parentheses.

$y = \frac{(- 2) + 3}{(- 2) - 2}$

Simplify $\frac{(- 2) + 3}{(- 2) - 2}$ .

Add $- 2$ and $3$ .

$y = \frac{1}{- 2 - 2}$

Subtract $2$ from $- 2$ .

$y = \frac{1}{- 4}$

Move the negative in front of the fraction.

$y = - \frac{1}{4}$

Substitute $- 1$ for $x$ and find the result for $y$ .

$y = \frac{(- 1) + 3}{(- 1) - 2}$

Solve the equation for $y$ .

Remove parentheses.

$y = \frac{- 1 + 3}{(- 1) - 2}$

Remove parentheses.

$y = \frac{- 1 + 3}{- 1 - 2}$

Remove parentheses.

$y = \frac{(- 1) + 3}{(- 1) - 2}$

Simplify $\frac{(- 1) + 3}{(- 1) - 2}$ .

Add $- 1$ and $3$ .

$y = \frac{2}{- 1 - 2}$

Subtract $2$ from $- 1$ .

$y = \frac{2}{- 3}$

Move the negative in front of the fraction.

$y = - \frac{2}{3}$

Substitute $0$ for $x$ and find the result for $y$ .

$y = \frac{(0) + 3}{(0) - 2}$

Solve the equation for $y$ .

Remove parentheses.

$y = \frac{0 + 3}{(0) - 2}$

Remove parentheses.

$y = \frac{0 + 3}{0 - 2}$

Remove parentheses.

$y = \frac{(0) + 3}{(0) - 2}$

Simplify $\frac{(0) + 3}{(0) - 2}$ .

Add $0$ and $3$ .

$y = \frac{3}{0 - 2}$

Subtract $2$ from $0$ .

$y = \frac{3}{- 2}$

Move the negative in front of the fraction.

$y = - \frac{3}{2}$

Substitute $1$ for $x$ and find the result for $y$ .

$y = \frac{(1) + 3}{(1) - 2}$

Solve the equation for $y$ .

Remove parentheses.

$y = \frac{1 + 3}{(1) - 2}$

Remove parentheses.

$y = \frac{1 + 3}{1 - 2}$

Remove parentheses.

$y = \frac{(1) + 3}{(1) - 2}$

Simplify $\frac{(1) + 3}{(1) - 2}$ .

Add $1$ and $3$ .

$y = \frac{4}{1 - 2}$

Subtract $2$ from $1$ .

$y = \frac{4}{- 1}$

Divide $4$ by $- 1$ .

$y = - 4$

This is a table of possible values to use when graphing the equation.

$\begin{array}{c} x & y \\ - 2 & - \frac{1}{4} \\ - 1 & - \frac{2}{3} \\ 0 & - \frac{3}{2} \\ 1 & - 4 \end{array}$

Graph Using a Table of Values f(x)=(x+3)/(x-2)

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