Graph Using a Table of Values g(x)=(1/2)^(x+1)

$g (x) = {(\frac{1}{2})}^{x + 1}$

Substitute $- 2$ for $x$ and find the result for $y$ .

$y = {(\frac{1}{2})}^{(- 2) + 1}$

Solve the equation for $y$ .

Remove parentheses.

$y = {(\frac{1}{2})}^{- 2 + 1}$

Remove parentheses.

$y = {(\frac{1}{2})}^{(- 2) + 1}$

Simplify ${(\frac{1}{2})}^{(- 2) + 1}$ .

Add $- 2$ and $1$ .

$y = {(\frac{1}{2})}^{- 1}$

Change the sign of the exponent by rewriting the base as its reciprocal.

$y = 2$

Substitute $- 1$ for $x$ and find the result for $y$ .

$y = {(\frac{1}{2})}^{(- 1) + 1}$

Solve the equation for $y$ .

Remove parentheses.

$y = {(\frac{1}{2})}^{- 1 + 1}$

Remove parentheses.

$y = {(\frac{1}{2})}^{(- 1) + 1}$

Simplify ${(\frac{1}{2})}^{(- 1) + 1}$ .

Add $- 1$ and $1$ .

$y = {(\frac{1}{2})}^{0}$

Apply the product rule to $\frac{1}{2}$ .

$y = \frac{1^{0}}{2^{0}}$

Anything raised to $0$ is $1$ .

$y = \frac{1}{2^{0}}$

Anything raised to $0$ is $1$ .

$y = \frac{1}{1}$

Divide $1$ by $1$ .

$y = 1$

Substitute $0$ for $x$ and find the result for $y$ .

$y = {(\frac{1}{2})}^{(0) + 1}$

Solve the equation for $y$ .

Remove parentheses.

$y = {(\frac{1}{2})}^{0 + 1}$

Remove parentheses.

$y = {(\frac{1}{2})}^{(0) + 1}$

Simplify ${(\frac{1}{2})}^{(0) + 1}$ .

Add $0$ and $1$ .

$y = {(\frac{1}{2})}^{1}$

Simplify.

$y = \frac{1}{2}$

Substitute $1$ for $x$ and find the result for $y$ .

$y = {(\frac{1}{2})}^{(1) + 1}$

Solve the equation for $y$ .

Remove parentheses.

$y = {(\frac{1}{2})}^{1 + 1}$

Remove parentheses.

$y = {(\frac{1}{2})}^{(1) + 1}$

Simplify ${(\frac{1}{2})}^{(1) + 1}$ .

Add $1$ and $1$ .

$y = {(\frac{1}{2})}^{2}$

Apply the product rule to $\frac{1}{2}$ .

$y = \frac{1^{2}}{2^{2}}$

One to any power is one.

$y = \frac{1}{2^{2}}$

Raise $2$ to the power of $2$ .

$y = \frac{1}{4}$

Substitute $2$ for $x$ and find the result for $y$ .

$y = {(\frac{1}{2})}^{(2) + 1}$

Solve the equation for $y$ .

Remove parentheses.

$y = {(\frac{1}{2})}^{2 + 1}$

Remove parentheses.

$y = {(\frac{1}{2})}^{(2) + 1}$

Simplify ${(\frac{1}{2})}^{(2) + 1}$ .

Add $2$ and $1$ .

$y = {(\frac{1}{2})}^{3}$

Apply the product rule to $\frac{1}{2}$ .

$y = \frac{1^{3}}{2^{3}}$

One to any power is one.

$y = \frac{1}{2^{3}}$

Raise $2$ to the power of $3$ .

$y = \frac{1}{8}$

This is a table of possible values to use when graphing the equation.

$\begin{array}{c} x & y \\ - 2 & 2 \\ - 1 & 1 \\ 0 & \frac{1}{2} \\ 1 & \frac{1}{4} \\ 2 & \frac{1}{8} \end{array}$

Graph Using a Table of Values g(x)=(1/2)^(x+1)

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