Graph Using a Table of Values y=1/(x+3)

$y = \frac{1}{x + 3}$

Substitute $- 2$ for $x$ and find the result for $y$ .

$y = \frac{1}{(- 2) + 3}$

Solve the equation for $y$ .

Remove parentheses.

$y = \frac{1}{- 2 + 3}$

Remove parentheses.

$y = \frac{1}{(- 2) + 3}$

Simplify $\frac{1}{(- 2) + 3}$ .

Add $- 2$ and $3$ .

$y = \frac{1}{1}$

Divide $1$ by $1$ .

$y = 1$

Substitute $- 1$ for $x$ and find the result for $y$ .

$y = \frac{1}{(- 1) + 3}$

Solve the equation for $y$ .

Remove parentheses.

$y = \frac{1}{- 1 + 3}$

Remove parentheses.

$y = \frac{1}{(- 1) + 3}$

Add $- 1$ and $3$ .

$y = \frac{1}{2}$

Substitute $0$ for $x$ and find the result for $y$ .

$y = \frac{1}{(0) + 3}$

Solve the equation for $y$ .

Remove parentheses.

$y = \frac{1}{0 + 3}$

Remove parentheses.

$y = \frac{1}{(0) + 3}$

Add $0$ and $3$ .

$y = \frac{1}{3}$

Substitute $1$ for $x$ and find the result for $y$ .

$y = \frac{1}{(1) + 3}$

Solve the equation for $y$ .

Remove parentheses.

$y = \frac{1}{1 + 3}$

Remove parentheses.

$y = \frac{1}{(1) + 3}$

Add $1$ and $3$ .

$y = \frac{1}{4}$

Substitute $2$ for $x$ and find the result for $y$ .

$y = \frac{1}{(2) + 3}$

Solve the equation for $y$ .

Remove parentheses.

$y = \frac{1}{2 + 3}$

Remove parentheses.

$y = \frac{1}{(2) + 3}$

Add $2$ and $3$ .

$y = \frac{1}{5}$

This is a table of possible values to use when graphing the equation.

$\begin{array}{c} x & y \\ - 2 & 1 \\ - 1 & \frac{1}{2} \\ 0 & \frac{1}{3} \\ 1 & \frac{1}{4} \\ 2 & \frac{1}{5} \end{array}$

Graph Using a Table of Values y=1/(x+3)

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