Graph Using a Table of Values y = log base 2 of x+5

$y = \log_{2} (x + 5)$

Substitute $- 2$ for $x$ and find the result for $y$ .

$y = \log_{2} ((- 2) + 5)$

Solve the equation for $y$ .

Remove parentheses.

$y = \log_{2} (- 2 + 5)$

Remove parentheses.

$y = \log_{2} ((- 2) + 5)$

Add $- 2$ and $5$ .

$y = \log_{2} (3)$

Substitute $- 1$ for $x$ and find the result for $y$ .

$y = \log_{2} ((- 1) + 5)$

Solve the equation for $y$ .

Remove parentheses.

$y = \log_{2} (- 1 + 5)$

Remove parentheses.

$y = \log_{2} ((- 1) + 5)$

Simplify $\log_{2} ((- 1) + 5)$ .

Add $- 1$ and $5$ .

$y = \log_{2} (4)$

Logarithm base $2$ of $4$ is $2$ .

Rewrite as an equation.

$y = \log_{2} (4) = x$

Rewrite $\log_{2} (4) = x$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b$ does not equal $1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$y = 2^{x} = 4$

Create equivalent expressions in the equation that all have equal bases.

$y = 2^{x} = 2^{2}$

Since the bases are the same, the two expressions are only equal if the exponents are also equal.

$y = x = 2$

The variable $x$ is equal to $2$ .

$y = 2$

Substitute $0$ for $x$ and find the result for $y$ .

$y = \log_{2} ((0) + 5)$

Solve the equation for $y$ .

Remove parentheses.

$y = \log_{2} (0 + 5)$

Remove parentheses.

$y = \log_{2} ((0) + 5)$

Add $0$ and $5$ .

$y = \log_{2} (5)$

Substitute $1$ for $x$ and find the result for $y$ .

$y = \log_{2} ((1) + 5)$

Solve the equation for $y$ .

Remove parentheses.

$y = \log_{2} (1 + 5)$

Remove parentheses.

$y = \log_{2} ((1) + 5)$

Add $1$ and $5$ .

$y = \log_{2} (6)$

Substitute $2$ for $x$ and find the result for $y$ .

$y = \log_{2} ((2) + 5)$

Solve the equation for $y$ .

Remove parentheses.

$y = \log_{2} (2 + 5)$

Remove parentheses.

$y = \log_{2} ((2) + 5)$

Add $2$ and $5$ .

$y = \log_{2} (7)$

This is a table of possible values to use when graphing the equation.

$\begin{array}{c} x & y \\ - 2 & \log_{2} (3) \\ - 1 & 2 \\ 0 & \log_{2} (5) \\ 1 & \log_{2} (6) \\ 2 & \log_{2} (7) \end{array}$

Graph Using a Table of Values y = log base 2 of x+5

Related Questions

Support LCMGCF.com by disabling your adblocker.