Graph Using a Table of Values y = square root of x+2

$y = \sqrt{x + 2}$

Substitute $- 2$ for $x$ and find the result for $y$ .

$y = \sqrt{(- 2) + 2}$

Simplify $\sqrt{(- 2) + 2}$ .

Add $- 2$ and $2$ .

$y = \sqrt{0}$

Rewrite $0$ as $0^{2}$ .

$y = \sqrt{0^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$y = 0$

Substitute $- 1$ for $x$ and find the result for $y$ .

$y = \sqrt{(- 1) + 2}$

Simplify $\sqrt{(- 1) + 2}$ .

Add $- 1$ and $2$ .

$y = \sqrt{1}$

Any root of $1$ is $1$ .

$y = 1$

Substitute $0$ for $x$ and find the result for $y$ .

$y = \sqrt{(0) + 2}$

Add $0$ and $2$ .

$y = \sqrt{2}$

Substitute $1$ for $x$ and find the result for $y$ .

$y = \sqrt{(1) + 2}$

Add $1$ and $2$ .

$y = \sqrt{3}$

Substitute $2$ for $x$ and find the result for $y$ .

$y = \sqrt{(2) + 2}$

Simplify $\sqrt{(2) + 2}$ .

Add $2$ and $2$ .

$y = \sqrt{4}$

Rewrite $4$ as $2^{2}$ .

$y = \sqrt{2^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$y = 2$

This is a table of possible values to use when graphing the equation.

$\begin{array}{c} x & y \\ - 2 & 0 \\ - 1 & 1 \\ 0 & \sqrt{2} \\ 1 & \sqrt{3} \\ 2 & 2 \end{array}$