Graph -x^2+12x-36>y

$- x^{2} + 12 x - 36 > y$

Rewrite so $y$ is on the left side of the inequality.

$y < - x^{2} + 12 x - 36$

The equation is not linear, so a constant slope does not exist.

Not Linear

Graph a dashed line, then shade the area below the boundary line since $y$ is less than $- x^{2} + 12 x - 36$ .

$y < - x^{2} + 12 x - 36$