Graph x^2(x-3)

$x^{2} (x - 3)$

Find the point at $x = - 1$ .

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = {(- 1)}^{3} - 3 {(- 1)}^{2}$

Simplify the result.

Simplify each term.

Raise $- 1$ to the power of $3$ .

$f (- 1) = - 1 - 3 {(- 1)}^{2}$

Raise $- 1$ to the power of $2$ .

$f (- 1) = - 1 - 3 \cdot 1$

Multiply $- 3$ by $1$ .

$f (- 1) = - 1 - 3$

Subtract $3$ from $- 1$ .

$f (- 1) = - 4$

The final answer is $- 4$ .

$- 4$

Convert $- 4$ to decimal.

$y = - 4$

Find the point at $x = 0$ .

Replace the variable $x$ with $0$ in the expression.

$f (0) = {(0)}^{3} - 3 {(0)}^{2}$

Simplify the result.

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$f (0) = 0 - 3 {(0)}^{2}$

Raising $0$ to any positive power yields $0$ .

$f (0) = 0 - 3 \cdot 0$

Multiply $- 3$ by $0$ .

$f (0) = 0 + 0$

Add $0$ and $0$ .

$f (0) = 0$

The final answer is $0$ .

$0$

Convert $0$ to decimal.

$y = 0$

Find the point at $x = 1$ .

Replace the variable $x$ with $1$ in the expression.

$f (1) = {(1)}^{3} - 3 {(1)}^{2}$

Simplify the result.

Simplify each term.

One to any power is one.

$f (1) = 1 - 3 {(1)}^{2}$

One to any power is one.

$f (1) = 1 - 3 \cdot 1$

Multiply $- 3$ by $1$ .

$f (1) = 1 - 3$

Subtract $3$ from $1$ .

$f (1) = - 2$

The final answer is $- 2$ .

$- 2$

Convert $- 2$ to decimal.

$y = - 2$

Find the point at $x = 2$ .

Replace the variable $x$ with $2$ in the expression.

$f (2) = {(2)}^{3} - 3 {(2)}^{2}$

Simplify the result.

Simplify each term.

Raise $2$ to the power of $3$ .

$f (2) = 8 - 3 {(2)}^{2}$

Raise $2$ to the power of $2$ .

$f (2) = 8 - 3 \cdot 4$

Multiply $- 3$ by $4$ .

$f (2) = 8 - 12$

Subtract $12$ from $8$ .

$f (2) = - 4$

The final answer is $- 4$ .

$- 4$

Convert $- 4$ to decimal.

$y = - 4$

Find the point at $x = 3$ .

Replace the variable $x$ with $3$ in the expression.

$f (3) = {(3)}^{3} - 3 {(3)}^{2}$

Simplify the result.

Simplify each term.

Raise $3$ to the power of $3$ .

$f (3) = 27 - 3 {(3)}^{2}$

Raise $3$ to the power of $2$ .

$f (3) = 27 - 3 \cdot 9$

Multiply $- 3$ by $9$ .

$f (3) = 27 - 27$

Subtract $27$ from $27$ .

$f (3) = 0$

The final answer is $0$ .

$0$

Convert $0$ to decimal.

$y = 0$

The cubic function can be graphed using the function behavior and the points.

$\begin{array}{c} x & y \\ - 1 & - 4 \\ 0 & 0 \\ 1 & - 2 \\ 2 & - 4 \\ 3 & 0 \end{array}$

The cubic function can be graphed using the function behavior and the selected points.

Falls to the left and rises to the right

$\begin{array}{c} x & y \\ - 1 & - 4 \\ 0 & 0 \\ 1 & - 2 \\ 2 & - 4 \\ 3 & 0 \end{array}$

Graph x^2(x-3)

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