Graph -x^2+y>=3

$- x^{2} + y \geq 3$

Add $x^{2}$ to both sides of the inequality.

$y \geq 3 + x^{2}$

Find the slope and the y-intercept for the boundary line.

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Reorder $3$ and $x^{2}$ .

$y \geq x^{2} + 3$

The equation is not linear, so a constant slope does not exist.

Not Linear

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $3 + x^{2}$ .

$y \geq 3 + x^{2}$