Graph x^2+y>3

$x^{2} + y > 3$

Step 1

Subtract $x^{2}$ from both sides of the inequality.

$y > 3 - x^{2}$

Step 2

Find the slope and the y-intercept for the boundary line.

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Reorder $3$ and $- x^{2}$ .

$y > - x^{2} + 3$

The equation is not linear, so a constant slope does not exist.

Not Linear

Step 3

Graph a dashed line, then shade the area above the boundary line since $y$ is greater than $3 - x^{2}$ .

$y > 3 - x^{2}$

Step 4