Graph x^2+y<=-4

$x^{2} + y \leq - 4$

Step 1

Subtract $x^{2}$ from both sides of the inequality.

$y \leq - 4 - x^{2}$

Step 2

Find the slope and the y-intercept for the boundary line.

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Reorder $- 4$ and $- x^{2}$ .

$y \leq - x^{2} - 4$

The equation is not linear, so a constant slope does not exist.

Not Linear

Step 3

Graph a solid line, then shade the area below the boundary line since $y$ is less than $- 4 - x^{2}$ .

$y \leq - 4 - x^{2}$

Step 4