Graph x>=-2 y>=x-2 x+y<=2

$x \geq - 2$ $y \geq x - 2$ $x + y \leq 2$

Graph $x \geq - 2$ .

$x \geq - 2$

Graph $y \geq x - 2$ .

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 1$

$b = - 2$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $1$

y-intercept: $(0, - 2)$

Slope: $1$

y-intercept: $(0, - 2)$

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $x - 2$ .

$y \geq x - 2$

Graph $x + y \leq 2$ .

Write in $y = m x + b$ form.

Subtract $x$ from both sides of the inequality.

$y \leq 2 - x$

Rearrange terms.

$y \leq - x + 2$

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - 1$

$b = 2$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- 1$

y-intercept: $(0, 2)$

Slope: $- 1$

y-intercept: $(0, 2)$

Graph a solid line, then shade the area below the boundary line since $y$ is less than $- x + 2$ .

$y \leq - x + 2$

Plot each graph on the same coordinate system.

$x \geq - 2$

$y \geq x - 2$

$x + y \leq 2$