Graph x+2y>=-12 y<6x+7

$x + 2 y \geq - 12$ $y < 6 x + 7$

Graph $x + 2 y \geq - 12$ .

Write in $y = m x + b$ form.

Solve for $y$ .

Subtract $x$ from both sides of the inequality.

$2 y \geq - 12 - x$

Divide each term in $2 y \geq - 12 - x$ by $2$ and simplify.

Divide each term in $2 y \geq - 12 - x$ by $2$ .

$\frac{2 y}{2} \geq \frac{- 12}{2} + \frac{- x}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} \geq \frac{- 12}{2} + \frac{- x}{2}$

Divide $y$ by $1$ .

$y \geq \frac{- 12}{2} + \frac{- x}{2}$

Simplify the right side.

Simplify each term.

Divide $- 12$ by $2$ .

$y \geq - 6 + \frac{- x}{2}$

Move the negative in front of the fraction.

$y \geq - 6 - \frac{x}{2}$

Rearrange terms.

$y \geq - \frac{x}{2} - 6$

Reorder terms.

$y \geq - (\frac{1}{2} x) - 6$

Remove parentheses.

$y \geq - \frac{1}{2} x - 6$

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - \frac{1}{2}$

$b = - 6$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- \frac{1}{2}$

y-intercept: $(0, - 6)$

Slope: $- \frac{1}{2}$

y-intercept: $(0, - 6)$

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $- \frac{1}{2} x - 6$ .

$y \geq - \frac{1}{2} x - 6$

Graph $y < 6 x + 7$ .

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 6$

$b = 7$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $6$

y-intercept: $(0, 7)$

Slope: $6$

y-intercept: $(0, 7)$

Graph a dashed line, then shade the area below the boundary line since $y$ is less than $6 x + 7$ .

$y < 6 x + 7$

Plot each graph on the same coordinate system.

$x + 2 y \geq - 12$

$y < 6 x + 7$

Graph x+2y>=-12 y<6x+7

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