Graph x-2y<-16 x+y>=5

$x - 2 y < - 16$ $x + y \geq 5$

Graph $x - 2 y < - 16$ .

Write in $y = m x + b$ form.

Solve for $y$ .

Subtract $x$ from both sides of the inequality.

$- 2 y < - 16 - x$

Divide each term in $- 2 y < - 16 - x$ by $- 2$ and simplify.

Divide each term in $- 2 y < - 16 - x$ by $- 2$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 2 y}{- 2} > \frac{- 16}{- 2} + \frac{- x}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 y}{- 2} > \frac{- 16}{- 2} + \frac{- x}{- 2}$

Divide $y$ by $1$ .

$y > \frac{- 16}{- 2} + \frac{- x}{- 2}$

Simplify the right side.

Simplify each term.

Divide $- 16$ by $- 2$ .

$y > 8 + \frac{- x}{- 2}$

Dividing two negative values results in a positive value.

$y > 8 + \frac{x}{2}$

Rearrange terms.

$y > \frac{x}{2} + 8$

Reorder terms.

$y > \frac{1}{2} x + 8$

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = \frac{1}{2}$

$b = 8$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $\frac{1}{2}$

y-intercept: $(0, 8)$

Slope: $\frac{1}{2}$

y-intercept: $(0, 8)$

Graph a dashed line, then shade the area above the boundary line since $y$ is greater than $\frac{1}{2} x + 8$ .

$y > \frac{1}{2} x + 8$

Graph $x + y \geq 5$ .

Write in $y = m x + b$ form.

Subtract $x$ from both sides of the inequality.

$y \geq 5 - x$

Rearrange terms.

$y \geq - x + 5$

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - 1$

$b = 5$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- 1$

y-intercept: $(0, 5)$

Slope: $- 1$

y-intercept: $(0, 5)$

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $- x + 5$ .

$y \geq - x + 5$

Plot each graph on the same coordinate system.

$x - 2 y < - 16$

$x + y \geq 5$

Graph x-2y<-16 x+y>=5

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