Graph x+2y>4 2x-y<=6

$x + 2 y > 4$ $2 x - y \leq 6$

Graph $x + 2 y > 4$ .

Write in $y = m x + b$ form.

Solve for $y$ .

Subtract $x$ from both sides of the inequality.

$2 y > 4 - x$

Divide each term in $2 y > 4 - x$ by $2$ and simplify.

Divide each term in $2 y > 4 - x$ by $2$ .

$\frac{2 y}{2} > \frac{4}{2} + \frac{- x}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} > \frac{4}{2} + \frac{- x}{2}$

Divide $y$ by $1$ .

$y > \frac{4}{2} + \frac{- x}{2}$

Simplify the right side.

Simplify each term.

Divide $4$ by $2$ .

$y > 2 + \frac{- x}{2}$

Move the negative in front of the fraction.

$y > 2 - \frac{x}{2}$

Rearrange terms.

$y > - \frac{x}{2} + 2$

Reorder terms.

$y > - (\frac{1}{2} x) + 2$

Remove parentheses.

$y > - \frac{1}{2} x + 2$

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - \frac{1}{2}$

$b = 2$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- \frac{1}{2}$

y-intercept: $(0, 2)$

Slope: $- \frac{1}{2}$

y-intercept: $(0, 2)$

Graph a dashed line, then shade the area above the boundary line since $y$ is greater than $- \frac{1}{2} x + 2$ .

$y > - \frac{1}{2} x + 2$

Graph $2 x - y \leq 6$ .

Write in $y = m x + b$ form.

Solve for $y$ .

Subtract $2 x$ from both sides of the inequality.

$- y \leq 6 - 2 x$

Divide each term in $- y \leq 6 - 2 x$ by $- 1$ and simplify.

Divide each term in $- y \leq 6 - 2 x$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- y}{- 1} \geq \frac{6}{- 1} + \frac{- 2 x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} \geq \frac{6}{- 1} + \frac{- 2 x}{- 1}$

Divide $y$ by $1$ .

$y \geq \frac{6}{- 1} + \frac{- 2 x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $6$ by $- 1$ .

$y \geq - 6 + \frac{- 2 x}{- 1}$

Move the negative one from the denominator of $\frac{- 2 x}{- 1}$ .

$y \geq - 6 - 1 \cdot (- 2 x)$

Rewrite $- 1 \cdot (- 2 x)$ as $- (- 2 x)$ .

$y \geq - 6 - (- 2 x)$

Multiply $- 2$ by $- 1$ .

$y \geq - 6 + 2 x$

Rearrange terms.

$y \geq 2 x - 6$

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 2$

$b = - 6$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $2$

y-intercept: $(0, - 6)$

Slope: $2$

y-intercept: $(0, - 6)$

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $2 x - 6$ .

$y \geq 2 x - 6$

Plot each graph on the same coordinate system.

$x + 2 y > 4$

$2 x - y \leq 6$

Graph x+2y>4 2x-y<=6

Related Questions

Support LCMGCF.com by disabling your adblocker.