Graph -x+2y<=-4 3x+y>-1

$- x + 2 y \leq - 4$ $3 x + y > - 1$

Graph $- x + 2 y \leq - 4$ .

Write in $y = m x + b$ form.

Solve for $y$ .

Add $x$ to both sides of the inequality.

$2 y \leq - 4 + x$

Divide each term in $2 y \leq - 4 + x$ by $2$ and simplify.

Divide each term in $2 y \leq - 4 + x$ by $2$ .

$\frac{2 y}{2} \leq \frac{- 4}{2} + \frac{x}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} \leq \frac{- 4}{2} + \frac{x}{2}$

Divide $y$ by $1$ .

$y \leq \frac{- 4}{2} + \frac{x}{2}$

Simplify the right side.

Divide $- 4$ by $2$ .

$y \leq - 2 + \frac{x}{2}$

Rearrange terms.

$y \leq \frac{x}{2} - 2$

Reorder terms.

$y \leq \frac{1}{2} x - 2$

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = \frac{1}{2}$

$b = - 2$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $\frac{1}{2}$

y-intercept: $(0, - 2)$

Slope: $\frac{1}{2}$

y-intercept: $(0, - 2)$

Graph a solid line, then shade the area below the boundary line since $y$ is less than $\frac{1}{2} x - 2$ .

$y \leq \frac{1}{2} x - 2$

Graph $3 x + y > - 1$ .

Write in $y = m x + b$ form.

Subtract $3 x$ from both sides of the inequality.

$y > - 1 - 3 x$

Rearrange terms.

$y > - 3 x - 1$

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - 3$

$b = - 1$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- 3$

y-intercept: $(0, - 1)$

Slope: $- 3$

y-intercept: $(0, - 1)$

Graph a dashed line, then shade the area above the boundary line since $y$ is greater than $- 3 x - 1$ .

$y > - 3 x - 1$

Plot each graph on the same coordinate system.

$- x + 2 y \leq - 4$

$3 x + y > - 1$

Graph -x+2y<=-4 3x+y>-1

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