Graph x-3y=3 y=x+3

$x - 3 y = 3$ $y = x + 3$

Step 1

Graph $x - 3 y = 3$ .

Solve for $y$ .

Subtract $x$ from both sides of the equation.

$- 3 y = 3 - x$

Divide each term in $- 3 y = 3 - x$ by $- 3$ and simplify.

Divide each term in $- 3 y = 3 - x$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{3}{- 3} + \frac{- x}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{3}{- 3} + \frac{- x}{- 3}$

Divide $y$ by $1$ .

$y = \frac{3}{- 3} + \frac{- x}{- 3}$

Simplify the right side.

Simplify each term.

Divide $3$ by $- 3$ .

$y = - 1 + \frac{- x}{- 3}$

Dividing two negative values results in a positive value.

$y = - 1 + \frac{x}{3}$

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Reorder $- 1$ and $\frac{x}{3}$ .

$y = \frac{x}{3} - 1$

Reorder terms.

$y = \frac{1}{3} x - 1$

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = \frac{1}{3}$

$b = - 1$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $\frac{1}{3}$

y-intercept: $(0, - 1)$

Slope: $\frac{1}{3}$

y-intercept: $(0, - 1)$

Any line can be graphed using two points. Select two $x$ values, and plug them into the equation to find the corresponding $y$ values.

Write in $y = m x + b$ form.

Reorder $- 1$ and $\frac{x}{3}$ .

$y = \frac{x}{3} - 1$

Reorder terms.

$y = \frac{1}{3} x - 1$

Create a table of the $x$ and $y$ values.

$\begin{array}{c} x & y \\ 0 & - 1 \\ 3 & 0 \end{array}$

Graph the line using the slope and the y-intercept, or the points.

Slope: $\frac{1}{3}$

y-intercept: $(0, - 1)$

$\begin{array}{c} x & y \\ 0 & - 1 \\ 3 & 0 \end{array}$

Slope: $\frac{1}{3}$

y-intercept: $(0, - 1)$

$\begin{array}{c} x & y \\ 0 & - 1 \\ 3 & 0 \end{array}$

Step 2

Graph $y = x + 3$ .

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 1$

$b = 3$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $1$

y-intercept: $(0, 3)$

Slope: $1$

y-intercept: $(0, 3)$

Any line can be graphed using two points. Select two $x$ values, and plug them into the equation to find the corresponding $y$ values.

Create a table of the $x$ and $y$ values.

$\begin{array}{c} x & y \\ 0 & 3 \\ 1 & 4 \end{array}$

Graph the line using the slope and the y-intercept, or the points.

Slope: $1$

y-intercept: $(0, 3)$

$\begin{array}{c} x & y \\ 0 & 3 \\ 1 & 4 \end{array}$

Slope: $1$

y-intercept: $(0, 3)$

$\begin{array}{c} x & y \\ 0 & 3 \\ 1 & 4 \end{array}$

Step 3

Plot each graph on the same coordinate system.

$x - 3 y = 3$

$y = x + 3$

Step 4

Graph x-3y=3 y=x+3

Related Questions

Support LCMGCF.com by disabling your adblocker.