Graph x-4y<=4y

$x - 4 y \leq 4 y$

Write in $y = m x + b$ form.

Solve for $y$ .

Move all terms containing $y$ to the left side of the inequality.

Subtract $4 y$ from both sides of the inequality.

$x - 4 y - 4 y \leq 0$

Subtract $4 y$ from $- 4 y$ .

$x - 8 y \leq 0$

Subtract $x$ from both sides of the inequality.

$- 8 y \leq - x$

Divide each term in $- 8 y \leq - x$ by $- 8$ and simplify.

Divide each term in $- 8 y \leq - x$ by $- 8$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 8 y}{- 8} \geq \frac{- x}{- 8}$

Simplify the left side.

Cancel the common factor of $- 8$ .

Cancel the common factor.

$\frac{- 8 y}{- 8} \geq \frac{- x}{- 8}$

Divide $y$ by $1$ .

$y \geq \frac{- x}{- 8}$

Simplify the right side.

Dividing two negative values results in a positive value.

$y \geq \frac{x}{8}$

Reorder terms.

$y \geq \frac{1}{8} x$

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = \frac{1}{8}$

$b = 0$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $\frac{1}{8}$

y-intercept: $(0, 0)$

Slope: $\frac{1}{8}$

y-intercept: $(0, 0)$

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $\frac{1}{8} x$ .

$y \geq \frac{1}{8} x$

Graph x-4y<=4y

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