Graph ((x-5)^2)/25=1-((y+2)^2)/9

$\frac{{(x - 5)}^{2}}{25} = 1 - \frac{{(y + 2)}^{2}}{9}$

Step 1

Add $\frac{{(y + 2)}^{2}}{9}$ to both sides of the equation.

$\frac{{(x - 5)}^{2}}{25} + \frac{{(y + 2)}^{2}}{9} = 1$

Step 2

To write $\frac{{(x - 5)}^{2}}{25}$ as a fraction with a common denominator, multiply by $\frac{9}{9}$ .

$\frac{{(x - 5)}^{2}}{25} \cdot \frac{9}{9} + \frac{{(y + 2)}^{2}}{9} = 1$

Step 3

To write $\frac{{(y + 2)}^{2}}{9}$ as a fraction with a common denominator, multiply by $\frac{25}{25}$ .

$\frac{{(x - 5)}^{2}}{25} \cdot \frac{9}{9} + \frac{{(y + 2)}^{2}}{9} \cdot \frac{25}{25} = 1$

Step 4

Write each expression with a common denominator of $225$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{{(x - 5)}^{2}}{25}$ by $\frac{9}{9}$ .

$\frac{{(x - 5)}^{2} \cdot 9}{25 \cdot 9} + \frac{{(y + 2)}^{2}}{9} \cdot \frac{25}{25} = 1$

Multiply $25$ by $9$ .

$\frac{{(x - 5)}^{2} \cdot 9}{225} + \frac{{(y + 2)}^{2}}{9} \cdot \frac{25}{25} = 1$

Multiply $\frac{{(y + 2)}^{2}}{9}$ by $\frac{25}{25}$ .

$\frac{{(x - 5)}^{2} \cdot 9}{225} + \frac{{(y + 2)}^{2} \cdot 25}{9 \cdot 25} = 1$

Multiply $9$ by $25$ .

$\frac{{(x - 5)}^{2} \cdot 9}{225} + \frac{{(y + 2)}^{2} \cdot 25}{225} = 1$

Step 5

Combine the numerators over the common denominator.

$\frac{{(x - 5)}^{2} \cdot 9 + {(y + 2)}^{2} \cdot 25}{225} = 1$

Step 6

Simplify the numerator.

Rewrite ${(x - 5)}^{2}$ as $(x - 5) (x - 5)$ .

$\frac{(x - 5) (x - 5) \cdot 9 + {(y + 2)}^{2} \cdot 25}{225} = 1$

Expand $(x - 5) (x - 5)$ using the FOIL Method.

Apply the distributive property.

$\frac{(x (x - 5) - 5 (x - 5)) \cdot 9 + {(y + 2)}^{2} \cdot 25}{225} = 1$

Apply the distributive property.

$\frac{(x \cdot x + x \cdot - 5 - 5 (x - 5)) \cdot 9 + {(y + 2)}^{2} \cdot 25}{225} = 1$

Apply the distributive property.

$\frac{(x \cdot x + x \cdot - 5 - 5 x - 5 \cdot - 5) \cdot 9 + {(y + 2)}^{2} \cdot 25}{225} = 1$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$\frac{(x^{2} + x \cdot - 5 - 5 x - 5 \cdot - 5) \cdot 9 + {(y + 2)}^{2} \cdot 25}{225} = 1$

Move $- 5$ to the left of $x$ .

$\frac{(x^{2} - 5 \cdot x - 5 x - 5 \cdot - 5) \cdot 9 + {(y + 2)}^{2} \cdot 25}{225} = 1$

Multiply $- 5$ by $- 5$ .

$\frac{(x^{2} - 5 x - 5 x + 25) \cdot 9 + {(y + 2)}^{2} \cdot 25}{225} = 1$

Subtract $5 x$ from $- 5 x$ .

$\frac{(x^{2} - 10 x + 25) \cdot 9 + {(y + 2)}^{2} \cdot 25}{225} = 1$

Apply the distributive property.

$\frac{x^{2} \cdot 9 - 10 x \cdot 9 + 25 \cdot 9 + {(y + 2)}^{2} \cdot 25}{225} = 1$

Simplify.

Move $9$ to the left of $x^{2}$ .

$\frac{9 \cdot x^{2} - 10 x \cdot 9 + 25 \cdot 9 + {(y + 2)}^{2} \cdot 25}{225} = 1$

Multiply $9$ by $- 10$ .

$\frac{9 \cdot x^{2} - 90 x + 25 \cdot 9 + {(y + 2)}^{2} \cdot 25}{225} = 1$

Multiply $25$ by $9$ .

$\frac{9 \cdot x^{2} - 90 x + 225 + {(y + 2)}^{2} \cdot 25}{225} = 1$

Rewrite ${(y + 2)}^{2}$ as $(y + 2) (y + 2)$ .

$\frac{9 x^{2} - 90 x + 225 + (y + 2) (y + 2) \cdot 25}{225} = 1$

Expand $(y + 2) (y + 2)$ using the FOIL Method.

Apply the distributive property.

$\frac{9 x^{2} - 90 x + 225 + (y (y + 2) + 2 (y + 2)) \cdot 25}{225} = 1$

Apply the distributive property.

$\frac{9 x^{2} - 90 x + 225 + (y \cdot y + y \cdot 2 + 2 (y + 2)) \cdot 25}{225} = 1$

Apply the distributive property.

$\frac{9 x^{2} - 90 x + 225 + (y \cdot y + y \cdot 2 + 2 y + 2 \cdot 2) \cdot 25}{225} = 1$

Simplify and combine like terms.

Simplify each term.

Multiply $y$ by $y$ .

$\frac{9 x^{2} - 90 x + 225 + (y^{2} + y \cdot 2 + 2 y + 2 \cdot 2) \cdot 25}{225} = 1$

Move $2$ to the left of $y$ .

$\frac{9 x^{2} - 90 x + 225 + (y^{2} + 2 \cdot y + 2 y + 2 \cdot 2) \cdot 25}{225} = 1$

Multiply $2$ by $2$ .

$\frac{9 x^{2} - 90 x + 225 + (y^{2} + 2 y + 2 y + 4) \cdot 25}{225} = 1$

Add $2 y$ and $2 y$ .

$\frac{9 x^{2} - 90 x + 225 + (y^{2} + 4 y + 4) \cdot 25}{225} = 1$

Apply the distributive property.

$\frac{9 x^{2} - 90 x + 225 + y^{2} \cdot 25 + 4 y \cdot 25 + 4 \cdot 25}{225} = 1$

Simplify.

Move $25$ to the left of $y^{2}$ .

$\frac{9 x^{2} - 90 x + 225 + 25 \cdot y^{2} + 4 y \cdot 25 + 4 \cdot 25}{225} = 1$

Multiply $25$ by $4$ .

$\frac{9 x^{2} - 90 x + 225 + 25 \cdot y^{2} + 100 y + 4 \cdot 25}{225} = 1$

Multiply $4$ by $25$ .

$\frac{9 x^{2} - 90 x + 225 + 25 \cdot y^{2} + 100 y + 100}{225} = 1$

Add $225$ and $100$ .

$\frac{9 x^{2} - 90 x + 25 y^{2} + 100 y + 325}{225} = 1$

Step 7

Graph ((x-5)^2)/25=1-((y+2)^2)/9

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