Graph x=5y^2

$x = 5 y^{2}$

Step 1

Find the properties of the given parabola.

Rewrite the equation in vertex form.

Complete the square for $5 y^{2}$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 5$

$b = 0$

$c = 0$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{0}{2 \cdot 5}$

Simplify the right side.

Cancel the common factor of $0$ and $2$ .

Factor $2$ out of $0$ .

$d = \frac{2 (0)}{2 \cdot 5}$

Cancel the common factors.

Factor $2$ out of $2 \cdot 5$ .

$d = \frac{2 (0)}{2 (5)}$

Cancel the common factor.

$d = \frac{2 \cdot 0}{2 \cdot 5}$

Rewrite the expression.

$d = \frac{0}{5}$

Cancel the common factor of $0$ and $5$ .

Factor $5$ out of $0$ .

$d = \frac{5 (0)}{5}$

Cancel the common factors.

Factor $5$ out of $5$ .

$d = \frac{5 \cdot 0}{5 \cdot 1}$

Cancel the common factor.

$d = \frac{5 \cdot 0}{5 \cdot 1}$

Rewrite the expression.

$d = \frac{0}{1}$

Divide $0$ by $1$ .

$d = 0$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{0^{2}}{4 \cdot 5}$

Simplify the right side.

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$e = 0 - \frac{0}{4 \cdot 5}$

Multiply $4$ by $5$ .

$e = 0 - \frac{0}{20}$

Divide $0$ by $20$ .

$e = 0 - 0$

Multiply $- 1$ by $0$ .

$e = 0 + 0$

Add $0$ and $0$ .

$e = 0$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $5 y^{2}$ .

$5 y^{2}$

Set $x$ equal to the new right side.

$x = 5 y^{2}$

Use the vertex form, $x = a {(y - k)}^{2} + h$ , to determine the values of $a$ , $h$ , and $k$ .

$a = 5$

$h = 0$

$k = 0$

Since the value of $a$ is positive, the parabola opens right.

Opens Right

Find the vertex $(h, k)$ .

$(0, 0)$

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot 5}$

Multiply $4$ by $5$ .

$\frac{1}{20}$

Find the focus.

The focus of a parabola can be found by adding $p$ to the x-coordinate $h$ if the parabola opens left or right.

$(h + p, k)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(\frac{1}{20}, 0)$

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$y = 0$

Find the directrix.

The directrix of a parabola is the vertical line found by subtracting $p$ from the x-coordinate $h$ of the vertex if the parabola opens left or right.

$x = h - p$

Substitute the known values of $p$ and $h$ into the formula and simplify.

$x = - \frac{1}{20}$

Use the properties of the parabola to analyze and graph the parabola.

Direction: Opens Right

Vertex: $(0, 0)$

Focus: $(\frac{1}{20}, 0)$

Axis of Symmetry: $y = 0$

Directrix: $x = - \frac{1}{20}$

Direction: Opens Right

Vertex: $(0, 0)$

Focus: $(\frac{1}{20}, 0)$

Axis of Symmetry: $y = 0$

Directrix: $x = - \frac{1}{20}$

Step 2

Select a few $x$ values, and plug them into the equation to find the corresponding $y$ values. The $x$ values should be selected around the vertex.

Substitute the $x$ value $1$ into $f (x) = \frac{\sqrt{5 x}}{5}$ . In this case, the point is $(1, 0.44721359)$ .

Replace the variable $x$ with $1$ in the expression.

$f (1) = \frac{\sqrt{5 (1)}}{5}$

Simplify the result.

Multiply $5$ by $1$ .

$f (1) = \frac{\sqrt{5}}{5}$

The final answer is $\frac{\sqrt{5}}{5}$ .

$y = \frac{\sqrt{5}}{5}$

Convert $\frac{\sqrt{5}}{5}$ to decimal.

$= 0.44721359$

Substitute the $x$ value $1$ into $f (x) = - \frac{\sqrt{5 x}}{5}$ . In this case, the point is $(1, - 0.44721359)$ .

Replace the variable $x$ with $1$ in the expression.

$f (1) = - \frac{\sqrt{5 (1)}}{5}$

Simplify the result.

Multiply $5$ by $1$ .

$f (1) = - \frac{\sqrt{5}}{5}$

The final answer is $- \frac{\sqrt{5}}{5}$ .

$y = - \frac{\sqrt{5}}{5}$

Convert $- \frac{\sqrt{5}}{5}$ to decimal.

$= - 0.44721359$

Substitute the $x$ value $2$ into $f (x) = \frac{\sqrt{5 x}}{5}$ . In this case, the point is $(2, 0.63245553)$ .

Replace the variable $x$ with $2$ in the expression.

$f (2) = \frac{\sqrt{5 (2)}}{5}$

Simplify the result.

Multiply $5$ by $2$ .

$f (2) = \frac{\sqrt{10}}{5}$

The final answer is $\frac{\sqrt{10}}{5}$ .

$y = \frac{\sqrt{10}}{5}$

Convert $\frac{\sqrt{10}}{5}$ to decimal.

$= 0.63245553$

Substitute the $x$ value $2$ into $f (x) = - \frac{\sqrt{5 x}}{5}$ . In this case, the point is $(2, - 0.63245553)$ .

Replace the variable $x$ with $2$ in the expression.

$f (2) = - \frac{\sqrt{5 (2)}}{5}$

Simplify the result.

Multiply $5$ by $2$ .

$f (2) = - \frac{\sqrt{10}}{5}$

The final answer is $- \frac{\sqrt{10}}{5}$ .

$y = - \frac{\sqrt{10}}{5}$

Convert $- \frac{\sqrt{10}}{5}$ to decimal.

$= - 0.63245553$

Graph the parabola using its properties and the selected points.

$\begin{array}{c} x & y \\ 0 & 0 \\ 1 & 0.45 \\ 1 & - 0.45 \\ 2 & 0.63 \\ 2 & - 0.63 \end{array}$

Step 3

Graph the parabola using its properties and the selected points.

Direction: Opens Right

Vertex: $(0, 0)$

Focus: $(\frac{1}{20}, 0)$

Axis of Symmetry: $y = 0$

Directrix: $x = - \frac{1}{20}$

$\begin{array}{c} x & y \\ 0 & 0 \\ 1 & 0.45 \\ 1 & - 0.45 \\ 2 & 0.63 \\ 2 & - 0.63 \end{array}$

Step 4

Graph x=5y^2

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