Graph x+y>=0 2x-y>=1

$x + y \geq 0$ $2 x - y \geq 1$

Graph $x + y \geq 0$ .

Subtract $x$ from both sides of the inequality.

$y \geq - x$

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - 1$

$b = 0$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- 1$

y-intercept: $(0, 0)$

Slope: $- 1$

y-intercept: $(0, 0)$

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $- x$ .

$y \geq - x$

Graph $2 x - y \geq 1$ .

Write in $y = m x + b$ form.

Solve for $y$ .

Subtract $2 x$ from both sides of the inequality.

$- y \geq 1 - 2 x$

Divide each term in $- y \geq 1 - 2 x$ by $- 1$ and simplify.

Divide each term in $- y \geq 1 - 2 x$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- y}{- 1} \leq \frac{1}{- 1} + \frac{- 2 x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} \leq \frac{1}{- 1} + \frac{- 2 x}{- 1}$

Divide $y$ by $1$ .

$y \leq \frac{1}{- 1} + \frac{- 2 x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $1$ by $- 1$ .

$y \leq - 1 + \frac{- 2 x}{- 1}$

Move the negative one from the denominator of $\frac{- 2 x}{- 1}$ .

$y \leq - 1 - 1 \cdot (- 2 x)$

Rewrite $- 1 \cdot (- 2 x)$ as $- (- 2 x)$ .

$y \leq - 1 - (- 2 x)$

Multiply $- 2$ by $- 1$ .

$y \leq - 1 + 2 x$

Rearrange terms.

$y \leq 2 x - 1$

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 2$

$b = - 1$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $2$

y-intercept: $(0, - 1)$

Slope: $2$

y-intercept: $(0, - 1)$

Graph a solid line, then shade the area below the boundary line since $y$ is less than $2 x - 1$ .

$y \leq 2 x - 1$

Plot each graph on the same coordinate system.

$x + y \geq 0$

$2 x - y \geq 1$

Graph x+y>=0 2x-y>=1

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