Graph x=(y+1)^3-2

$x = {(y + 1)}^{3} - 2$

Step 1

Find the point at $x = - 2$ .

Replace the variable $x$ with $- 2$ in the expression.

$f (- 2) = \sqrt[3]{(- 2) + 2} - 1$

Simplify the result.

Simplify each term.

Add $- 2$ and $2$ .

$f (- 2) = \sqrt[3]{0} - 1$

Rewrite $0$ as $0^{3}$ .

$f (- 2) = \sqrt[3]{0^{3}} - 1$

Pull terms out from under the radical, assuming real numbers.

$f (- 2) = 0 - 1$

Subtract $1$ from $0$ .

$f (- 2) = - 1$

The final answer is $- 1$ .

$- 1$

Convert $- 1$ to decimal.

$y = - 1$

Step 2

Find the point at $x = - 1$ .

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = \sqrt[3]{(- 1) + 2} - 1$

Simplify the result.

Simplify each term.

Add $- 1$ and $2$ .

$f (- 1) = \sqrt[3]{1} - 1$

Any root of $1$ is $1$ .

$f (- 1) = 1 - 1$

Subtract $1$ from $1$ .

$f (- 1) = 0$

The final answer is $0$ .

$0$

Convert $0$ to decimal.

$y = 0$

Step 3

Find the point at $x = 0$ .

Replace the variable $x$ with $0$ in the expression.

$f (0) = \sqrt[3]{(0) + 2} - 1$

Simplify the result.

Add $0$ and $2$ .

$f (0) = \sqrt[3]{2} - 1$

The final answer is $\sqrt[3]{2} - 1$ .

$\sqrt[3]{2} - 1$

Convert $\sqrt[3]{2} - 1$ to decimal.

$y = 0.25992104$

Step 4

Find the point at $x = 1$ .

Replace the variable $x$ with $1$ in the expression.

$f (1) = \sqrt[3]{(1) + 2} - 1$

Simplify the result.

Add $1$ and $2$ .

$f (1) = \sqrt[3]{3} - 1$

The final answer is $\sqrt[3]{3} - 1$ .

$\sqrt[3]{3} - 1$

Convert $\sqrt[3]{3} - 1$ to decimal.

$y = 0.44224957$

Step 5

Find the point at $x = 2$ .

Replace the variable $x$ with $2$ in the expression.

$f (2) = \sqrt[3]{(2) + 2} - 1$

Simplify the result.

Add $2$ and $2$ .

$f (2) = \sqrt[3]{4} - 1$

The final answer is $\sqrt[3]{4} - 1$ .

$\sqrt[3]{4} - 1$

Convert $\sqrt[3]{4} - 1$ to decimal.

$y = 0.58740105$

Step 6

The cubic function can be graphed using the function behavior and the points.

$\begin{array}{c} x & y \\ - 2 & - 1 \\ - 1 & 0 \\ 0 & 0.26 \\ 1 & 0.442 \\ 2 & 0.587 \end{array}$

Step 7

The cubic function can be graphed using the function behavior and the selected points.

Not a polynomial

$\begin{array}{c} x & y \\ - 2 & - 1 \\ - 1 & 0 \\ 0 & 0.26 \\ 1 & 0.442 \\ 2 & 0.587 \end{array}$

Step 8

Graph x=(y+1)^3-2

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