Graph x>=y+2

$x \geq y + 2$

Solve for $y$ .

Rewrite so $y$ is on the left side of the inequality.

$y + 2 \leq x$

Subtract $2$ from both sides of the inequality.

$y \leq x - 2$

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 1$

$b = - 2$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $1$

y-intercept: $(0, - 2)$

Slope: $1$

y-intercept: $(0, - 2)$

Graph a solid line, then shade the area below the boundary line since $y$ is less than $x - 2$ .

$y \leq x - 2$