Graph x<y+3

$x < y + 3$

Step 1

Solve for $y$ .

Rewrite so $y$ is on the left side of the inequality.

$y + 3 > x$

Subtract $3$ from both sides of the inequality.

$y > x - 3$

Step 2

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 1$

$b = - 3$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $1$

y-intercept: $(0, - 3)$

Slope: $1$

y-intercept: $(0, - 3)$

Step 3

Graph a dashed line, then shade the area above the boundary line since $y$ is greater than $x - 3$ .

$y > x - 3$

Step 4