Graph x-y=3 7x-y=-3

$x - y = 3$ $7 x - y = - 3$

Graph $x - y = 3$ .

Solve for $y$ .

Subtract $x$ from both sides of the equation.

$- y = 3 - x$

Divide each term in $- y = 3 - x$ by $- 1$ and simplify.

Divide each term in $- y = 3 - x$ by $- 1$ .

$\frac{- y}{- 1} = \frac{3}{- 1} + \frac{- x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{3}{- 1} + \frac{- x}{- 1}$

Divide $y$ by $1$ .

$y = \frac{3}{- 1} + \frac{- x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $3$ by $- 1$ .

$y = - 3 + \frac{- x}{- 1}$

Dividing two negative values results in a positive value.

$y = - 3 + \frac{x}{1}$

Divide $x$ by $1$ .

$y = - 3 + x$

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Reorder $- 3$ and $x$ .

$y = x - 3$

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 1$

$b = - 3$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $1$

y-intercept: $(0, - 3)$

Slope: $1$

y-intercept: $(0, - 3)$

Any line can be graphed using two points. Select two $x$ values, and plug them into the equation to find the corresponding $y$ values.

Reorder $- 3$ and $x$ .

$y = x - 3$

Create a table of the $x$ and $y$ values.

$\begin{array}{c} x & y \\ 0 & - 3 \\ 1 & - 2 \end{array}$

Graph the line using the slope and the y-intercept, or the points.

Slope: $1$

y-intercept: $(0, - 3)$

$\begin{array}{c} x & y \\ 0 & - 3 \\ 1 & - 2 \end{array}$

Slope: $1$

y-intercept: $(0, - 3)$

$\begin{array}{c} x & y \\ 0 & - 3 \\ 1 & - 2 \end{array}$

Graph $7 x - y = - 3$ .

Solve for $y$ .

Subtract $7 x$ from both sides of the equation.

$- y = - 3 - 7 x$

Divide each term in $- y = - 3 - 7 x$ by $- 1$ and simplify.

Divide each term in $- y = - 3 - 7 x$ by $- 1$ .

$\frac{- y}{- 1} = \frac{- 3}{- 1} + \frac{- 7 x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{- 3}{- 1} + \frac{- 7 x}{- 1}$

Divide $y$ by $1$ .

$y = \frac{- 3}{- 1} + \frac{- 7 x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $- 3$ by $- 1$ .

$y = 3 + \frac{- 7 x}{- 1}$

Move the negative one from the denominator of $\frac{- 7 x}{- 1}$ .

$y = 3 - 1 \cdot (- 7 x)$

Rewrite $- 1 \cdot (- 7 x)$ as $- (- 7 x)$ .

$y = 3 - (- 7 x)$

Multiply $- 7$ by $- 1$ .

$y = 3 + 7 x$

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Reorder $3$ and $7 x$ .

$y = 7 x + 3$

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 7$

$b = 3$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $7$

y-intercept: $(0, 3)$

Slope: $7$

y-intercept: $(0, 3)$

Any line can be graphed using two points. Select two $x$ values, and plug them into the equation to find the corresponding $y$ values.

Reorder $3$ and $7 x$ .

$y = 7 x + 3$

Create a table of the $x$ and $y$ values.

$\begin{array}{c} x & y \\ 0 & 3 \\ 1 & 10 \end{array}$

Graph the line using the slope and the y-intercept, or the points.

Slope: $7$

y-intercept: $(0, 3)$

$\begin{array}{c} x & y \\ 0 & 3 \\ 1 & 10 \end{array}$

Slope: $7$

y-intercept: $(0, 3)$

$\begin{array}{c} x & y \\ 0 & 3 \\ 1 & 10 \end{array}$

Plot each graph on the same coordinate system.

$x - y = 3$

$7 x - y = - 3$

Graph x-y=3 7x-y=-3

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