Graph x-y<-6 x-y<=1

$x - y < - 6$ $x - y \leq 1$

Graph $x - y < - 6$ .

Write in $y = m x + b$ form.

Solve for $y$ .

Subtract $x$ from both sides of the inequality.

$- y < - 6 - x$

Divide each term in $- y < - 6 - x$ by $- 1$ and simplify.

Divide each term in $- y < - 6 - x$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- y}{- 1} > \frac{- 6}{- 1} + \frac{- x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} > \frac{- 6}{- 1} + \frac{- x}{- 1}$

Divide $y$ by $1$ .

$y > \frac{- 6}{- 1} + \frac{- x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $- 6$ by $- 1$ .

$y > 6 + \frac{- x}{- 1}$

Dividing two negative values results in a positive value.

$y > 6 + \frac{x}{1}$

Divide $x$ by $1$ .

$y > 6 + x$

Rearrange terms.

$y > x + 6$

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 1$

$b = 6$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $1$

y-intercept: $(0, 6)$

Slope: $1$

y-intercept: $(0, 6)$

Graph a dashed line, then shade the area above the boundary line since $y$ is greater than $x + 6$ .

$y > x + 6$

Graph $x - y \leq 1$ .

Write in $y = m x + b$ form.

Solve for $y$ .

Subtract $x$ from both sides of the inequality.

$- y \leq 1 - x$

Divide each term in $- y \leq 1 - x$ by $- 1$ and simplify.

Divide each term in $- y \leq 1 - x$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- y}{- 1} \geq \frac{1}{- 1} + \frac{- x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} \geq \frac{1}{- 1} + \frac{- x}{- 1}$

Divide $y$ by $1$ .

$y \geq \frac{1}{- 1} + \frac{- x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $1$ by $- 1$ .

$y \geq - 1 + \frac{- x}{- 1}$

Dividing two negative values results in a positive value.

$y \geq - 1 + \frac{x}{1}$

Divide $x$ by $1$ .

$y \geq - 1 + x$

Rearrange terms.

$y \geq x - 1$

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 1$

$b = - 1$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $1$

y-intercept: $(0, - 1)$

Slope: $1$

y-intercept: $(0, - 1)$

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $x - 1$ .

$y \geq x - 1$

Plot each graph on the same coordinate system.

$x - y < - 6$

$x - y \leq 1$

Graph x-y<-6 x-y<=1

Related Questions

Support LCMGCF.com by disabling your adblocker.