Graph y=1/2sec(2x)

$y = \frac{1}{2} \sec (2 x)$

Step 1

Find the asymptotes.

For any $y = \sec (x)$ , vertical asymptotes occur at $x = \frac{π}{2} + n π$ , where $n$ is an integer. Use the basic period for $y = s e c (x)$ , $(- \frac{π}{2}, \frac{3 π}{2})$ , to find the vertical asymptotes for $y = \frac{\sec (2 x)}{2}$ . Set the inside of the secant function, $b x + c$ , for $y = a \sec (b x + c) + d$ equal to $- \frac{π}{2}$ to find where the vertical asymptote occurs for $y = \frac{\sec (2 x)}{2}$ .

$2 x = - \frac{π}{2}$

Divide each term in $2 x = - \frac{π}{2}$ by $2$ and simplify.

Divide each term in $2 x = - \frac{π}{2}$ by $2$ .

$\frac{2 x}{2} = \frac{- \frac{π}{2}}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- \frac{π}{2}}{2}$

Divide $x$ by $1$ .

$x = \frac{- \frac{π}{2}}{2}$

Simplify the right side.

Multiply the numerator by the reciprocal of the denominator.

$x = - \frac{π}{2} \cdot \frac{1}{2}$

Multiply $- \frac{π}{2} \cdot \frac{1}{2}$ .

Multiply $\frac{1}{2}$ by $\frac{π}{2}$ .

$x = - \frac{π}{2 \cdot 2}$

Multiply $2$ by $2$ .

$x = - \frac{π}{4}$

Set the inside of the secant function $2 x$ equal to $\frac{3 π}{2}$ .

$2 x = \frac{3 π}{2}$

Divide each term in $2 x = \frac{3 π}{2}$ by $2$ and simplify.

Divide each term in $2 x = \frac{3 π}{2}$ by $2$ .

$\frac{2 x}{2} = \frac{\frac{3 π}{2}}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{\frac{3 π}{2}}{2}$

Divide $x$ by $1$ .

$x = \frac{\frac{3 π}{2}}{2}$

Simplify the right side.

Multiply the numerator by the reciprocal of the denominator.

$x = \frac{3 π}{2} \cdot \frac{1}{2}$

Multiply $\frac{3 π}{2} \cdot \frac{1}{2}$ .

Multiply $\frac{3 π}{2}$ by $\frac{1}{2}$ .

$x = \frac{3 π}{2 \cdot 2}$

Multiply $2$ by $2$ .

$x = \frac{3 π}{4}$

The basic period for $y = \frac{\sec (2 x)}{2}$ will occur at $(- \frac{π}{4}, \frac{3 π}{4})$ , where $- \frac{π}{4}$ and $\frac{3 π}{4}$ are vertical asymptotes.

$(- \frac{π}{4}, \frac{3 π}{4})$

Find the period $\frac{2 π}{| b |}$ to find where the vertical asymptotes exist. Vertical asymptotes occur every half period.

The absolute value is the distance between a number and zero. The distance between $0$ and $2$ is $2$ .

$\frac{2 π}{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 π}{2}$

Divide $π$ by $1$ .

$π$

The vertical asymptotes for $y = \frac{\sec (2 x)}{2}$ occur at $- \frac{π}{4}$ , $\frac{3 π}{4}$ , and every $x = \frac{π n}{2}$ , where $n$ is an integer. This is half of the period.

$x = \frac{π n}{2}$

Secant only has vertical asymptotes.

No Horizontal Asymptotes

No Oblique Asymptotes

Vertical Asymptotes: $x = \frac{π n}{2}$ where $n$ is an integer

No Horizontal Asymptotes

No Oblique Asymptotes

Vertical Asymptotes: $x = \frac{π n}{2}$ where $n$ is an integer

Step 2

Use the form $a \sec (b x - c) + d$ to find the variables used to find the amplitude, period, phase shift, and vertical shift.

$a = \frac{1}{2}$

$b = 2$

$c = 0$

$d = 0$

Step 3

Since the graph of the function $s e c$ does not have a maximum or minimum value, there can be no value for the amplitude.

Amplitude: None

Step 4

Find the period of $\frac{\sec (2 x)}{2}$ .

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Replace $b$ with $2$ in the formula for period.

$\frac{2 π}{| 2 |}$

The absolute value is the distance between a number and zero. The distance between $0$ and $2$ is $2$ .

$\frac{2 π}{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 π}{2}$

Divide $π$ by $1$ .

$π$

Step 5

Find the phase shift using the formula $\frac{c}{b}$ .

The phase shift of the function can be calculated from $\frac{c}{b}$ .

Phase Shift: $\frac{c}{b}$

Replace the values of $c$ and $b$ in the equation for phase shift.

Phase Shift: $\frac{0}{2}$

Divide $0$ by $2$ .

Phase Shift: $0$

Step 6

List the properties of the trigonometric function.

Amplitude: None

Period: $π$

Phase Shift: None

Vertical Shift: None

Step 7

The trig function can be graphed using the amplitude, period, phase shift, vertical shift, and the points.

Vertical Asymptotes: $x = \frac{π n}{2}$ where $n$ is an integer

Amplitude: None

Period: $π$

Phase Shift: None

Vertical Shift: None

Step 8

Graph y=1/2sec(2x)

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