Graph y<-1/2x+1 y<=x-2

$y < - \frac{1}{2} x + 1$ $y \leq x - 2$

Graph $y < - \frac{1}{2} x + 1$ .

Find the slope and the y-intercept for the boundary line.

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Simplify the right side.

Combine $x$ and $\frac{1}{2}$ .

$y < - \frac{x}{2} + 1$

Write in $y = m x + b$ form.

Reorder terms.

$y < - (\frac{1}{2} x) + 1$

Remove parentheses.

$y < - \frac{1}{2} x + 1$

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - \frac{1}{2}$

$b = 1$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- \frac{1}{2}$

y-intercept: $(0, 1)$

Slope: $- \frac{1}{2}$

y-intercept: $(0, 1)$

Slope: $- \frac{1}{2}$

y-intercept: $(0, 1)$

Graph a dashed line, then shade the area below the boundary line since $y$ is less than $- \frac{1}{2} x + 1$ .

$y < - \frac{1}{2} x + 1$

Graph $y \leq x - 2$ .

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 1$

$b = - 2$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $1$

y-intercept: $(0, - 2)$

Slope: $1$

y-intercept: $(0, - 2)$

Graph a solid line, then shade the area below the boundary line since $y$ is less than $x - 2$ .

$y \leq x - 2$

Plot each graph on the same coordinate system.

$y < - \frac{1}{2} x + 1$

$y \leq x - 2$