Graph y=1/2x+3 x=-6

$y = \frac{1}{2} x + 3$ $x = - 6$

Step 1

Graph $y = \frac{1}{2} x + 3$ .

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Reorder terms.

$y = \frac{1}{2} x + 3$

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = \frac{1}{2}$

$b = 3$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $\frac{1}{2}$

y-intercept: $(0, 3)$

Slope: $\frac{1}{2}$

y-intercept: $(0, 3)$

Any line can be graphed using two points. Select two $x$ values, and plug them into the equation to find the corresponding $y$ values.

Reorder terms.

$y = \frac{1}{2} x + 3$

Create a table of the $x$ and $y$ values.

$\begin{array}{c} x & y \\ 0 & 3 \\ 2 & 4 \end{array}$

Graph the line using the slope and the y-intercept, or the points.

Slope: $\frac{1}{2}$

y-intercept: $(0, 3)$

$\begin{array}{c} x & y \\ 0 & 3 \\ 2 & 4 \end{array}$

Slope: $\frac{1}{2}$

y-intercept: $(0, 3)$

$\begin{array}{c} x & y \\ 0 & 3 \\ 2 & 4 \end{array}$

Step 2

Graph $x = - 6$ .

Since $x = - 6$ is a vertical line, there is no y-intercept and the slope is undefined.

Slope: Undefined

y-intercept: No y-intercept

Find two points on the line.

$\begin{array}{c} x & y \\ - 6 & 0 \\ - 6 & 1 \end{array}$

Graph the line using the slope, y-intercept, and two points.

Slope: Undefined

y-intercept: No y-intercept

$\begin{array}{c} x & y \\ - 6 & 0 \\ - 6 & 1 \end{array}$

Slope: Undefined

y-intercept: No y-intercept

$\begin{array}{c} x & y \\ - 6 & 0 \\ - 6 & 1 \end{array}$

Step 3

Plot each graph on the same coordinate system.

$y = \frac{1}{2} x + 3$

$x = - 6$

Step 4

Graph y=1/2x+3 x=-6

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