Graph y>=(-1/3)x+4

$y \geq (- \frac{1}{3}) x + 4$

Step 1

Write in $y = m x + b$ form.

Solve for $y$ .

Multiply $- \frac{1}{3}$ by $x$ .

$y \geq - \frac{1}{3} x + 4$

Combine $x$ and $\frac{1}{3}$ .

$y \geq - \frac{x}{3} + 4$

Reorder terms.

$y \geq - (\frac{1}{3} x) + 4$

Remove parentheses.

$y \geq - \frac{1}{3} x + 4$

Step 2

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - \frac{1}{3}$

$b = 4$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- \frac{1}{3}$

y-intercept: $(0, 4)$

Slope: $- \frac{1}{3}$

y-intercept: $(0, 4)$

Step 3

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $- \frac{1}{3} x + 4$ .

$y \geq - \frac{1}{3} x + 4$

Step 4