Graph y<1/3x+1/2

$y < \frac{1}{3} x + \frac{1}{2}$

Find the slope and the y-intercept for the boundary line.

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Simplify the right side.

Combine $\frac{1}{3}$ and $x$ .

$y < \frac{x}{3} + \frac{1}{2}$

Reorder terms.

$y < \frac{1}{3} x + \frac{1}{2}$

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = \frac{1}{3}$

$b = \frac{1}{2}$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $\frac{1}{3}$

y-intercept: $(0, \frac{1}{2})$

Slope: $\frac{1}{3}$

y-intercept: $(0, \frac{1}{2})$

Slope: $\frac{1}{3}$

y-intercept: $(0, \frac{1}{2})$

Graph a dashed line, then shade the area below the boundary line since $y$ is less than $\frac{1}{3} x + \frac{1}{2}$ .

$y < \frac{1}{3} x + \frac{1}{2}$