Graph y>=-1/(3x)+2

$y \geq - \frac{1}{3 x} + 2$

The equation is not linear, so a constant slope does not exist.

Not Linear

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $- \frac{1}{3 x} + 2$ .

$y \geq - \frac{1}{3 x} + 2$