Graph y=-1/4cos(4x)

$y = - \frac{1}{4} \cos (4 x)$

Step 1

Use the form $a \cos (b x - c) + d$ to find the variables used to find the amplitude, period, phase shift, and vertical shift.

$a = - \frac{1}{4}$

$b = 4$

$c = 0$

$d = 0$

Step 2

Find the amplitude $| a |$ .

Amplitude: $\frac{1}{4}$

Step 3

Find the period of $- \frac{\cos (4 x)}{4}$ .

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Replace $b$ with $4$ in the formula for period.

$\frac{2 π}{| 4 |}$

The absolute value is the distance between a number and zero. The distance between $0$ and $4$ is $4$ .

$\frac{2 π}{4}$

Cancel the common factor of $2$ and $4$ .

Factor $2$ out of $2 π$ .

$\frac{2 (π)}{4}$

Cancel the common factors.

Factor $2$ out of $4$ .

$\frac{2 π}{2 \cdot 2}$

Cancel the common factor.

$\frac{2 π}{2 \cdot 2}$

Rewrite the expression.

$\frac{π}{2}$

Step 4

Find the phase shift using the formula $\frac{c}{b}$ .

The phase shift of the function can be calculated from $\frac{c}{b}$ .

Phase Shift: $\frac{c}{b}$

Replace the values of $c$ and $b$ in the equation for phase shift.

Phase Shift: $\frac{0}{4}$

Divide $0$ by $4$ .

Phase Shift: $0$

Step 5

List the properties of the trigonometric function.

Amplitude: $\frac{1}{4}$

Period: $\frac{π}{2}$

Phase Shift: None

Vertical Shift: None

Step 6

Select a few points to graph.

Find the point at $x = 0$ .

Replace the variable $x$ with $0$ in the expression.

$f (0) = - \frac{\cos (4 (0))}{4}$

Simplify the result.

Simplify the numerator.

Multiply $4$ by $0$ .

$f (0) = - \frac{\cos (0)}{4}$

The exact value of $\cos (0)$ is $1$ .

$f (0) = - \frac{1}{4}$

The final answer is $- \frac{1}{4}$ .

$- \frac{1}{4}$

Find the point at $x = \frac{π}{8}$ .

Replace the variable $x$ with $\frac{π}{8}$ in the expression.

$f (\frac{π}{8}) = - \frac{\cos (4 (\frac{π}{8}))}{4}$

Simplify the result.

Simplify the numerator.

Cancel the common factor of $4$ .

Factor $4$ out of $8$ .

$f (\frac{π}{8}) = - \frac{\cos (4 (\frac{π}{4 (2)}))}{4}$

Cancel the common factor.

$f (\frac{π}{8}) = - \frac{\cos (4 (\frac{π}{4 \cdot 2}))}{4}$

Rewrite the expression.

$f (\frac{π}{8}) = - \frac{\cos (\frac{π}{2})}{4}$

The exact value of $\cos (\frac{π}{2})$ is $0$ .

$f (\frac{π}{8}) = - \frac{0}{4}$

Simplify the expression.

Divide $0$ by $4$ .

$f (\frac{π}{8}) = - 0$

Multiply $- 1$ by $0$ .

$f (\frac{π}{8}) = 0$

The final answer is $0$ .

$0$

Find the point at $x = \frac{π}{4}$ .

Replace the variable $x$ with $\frac{π}{4}$ in the expression.

$f (\frac{π}{4}) = - \frac{\cos (4 (\frac{π}{4}))}{4}$

Simplify the result.

Simplify the numerator.

Cancel the common factor of $4$ .

Cancel the common factor.

$f (\frac{π}{4}) = - \frac{\cos (4 (\frac{π}{4}))}{4}$

Rewrite the expression.

$f (\frac{π}{4}) = - \frac{\cos (π)}{4}$

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because cosine is negative in the second quadrant.

$f (\frac{π}{4}) = - \frac{- \cos (0)}{4}$

The exact value of $\cos (0)$ is $1$ .

$f (\frac{π}{4}) = - \frac{- 1 \cdot 1}{4}$

Multiply $- 1$ by $1$ .

$f (\frac{π}{4}) = - \frac{- 1}{4}$

Move the negative in front of the fraction.

$f (\frac{π}{4}) = \frac{1}{4}$

The final answer is $\frac{1}{4}$ .

$\frac{1}{4}$

Find the point at $x = \frac{3 π}{8}$ .

Replace the variable $x$ with $\frac{3 π}{8}$ in the expression.

$f (\frac{3 π}{8}) = - \frac{\cos (4 (\frac{3 π}{8}))}{4}$

Simplify the result.

Simplify the numerator.

Cancel the common factor of $4$ .

Factor $4$ out of $8$ .

$f (\frac{3 π}{8}) = - \frac{\cos (4 (\frac{3 π}{4 (2)}))}{4}$

Cancel the common factor.

$f (\frac{3 π}{8}) = - \frac{\cos (4 (\frac{3 π}{4 \cdot 2}))}{4}$

Rewrite the expression.

$f (\frac{3 π}{8}) = - \frac{\cos (\frac{3 π}{2})}{4}$

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant.

$f (\frac{3 π}{8}) = - \frac{\cos (\frac{π}{2})}{4}$

The exact value of $\cos (\frac{π}{2})$ is $0$ .

$f (\frac{3 π}{8}) = - \frac{0}{4}$

Simplify the expression.

Divide $0$ by $4$ .

$f (\frac{3 π}{8}) = - 0$

Multiply $- 1$ by $0$ .

$f (\frac{3 π}{8}) = 0$

The final answer is $0$ .

$0$

Find the point at $x = \frac{π}{2}$ .

Replace the variable $x$ with $\frac{π}{2}$ in the expression.

$f (\frac{π}{2}) = - \frac{\cos (4 (\frac{π}{2}))}{4}$

Simplify the result.

Simplify the numerator.

Cancel the common factor of $2$ .

Factor $2$ out of $4$ .

$f (\frac{π}{2}) = - \frac{\cos (2 (2) (\frac{π}{2}))}{4}$

Cancel the common factor.

$f (\frac{π}{2}) = - \frac{\cos (2 \cdot (2 (\frac{π}{2})))}{4}$

Rewrite the expression.

$f (\frac{π}{2}) = - \frac{\cos (2 π)}{4}$

Subtract full rotations of $2 π$ until the angle is greater than or equal to $0$ and less than $2 π$ .

$f (\frac{π}{2}) = - \frac{\cos (0)}{4}$

The exact value of $\cos (0)$ is $1$ .

$f (\frac{π}{2}) = - \frac{1}{4}$

The final answer is $- \frac{1}{4}$ .

$- \frac{1}{4}$

List the points in a table.

$\begin{array}{c} x & f (x) \\ 0 & - \frac{1}{4} \\ \frac{π}{8} & 0 \\ \frac{π}{4} & \frac{1}{4} \\ \frac{3 π}{8} & 0 \\ \frac{π}{2} & - \frac{1}{4} \end{array}$

Step 7

The trig function can be graphed using the amplitude, period, phase shift, vertical shift, and the points.

Amplitude: $\frac{1}{4}$

Period: $\frac{π}{2}$

Phase Shift: None

Vertical Shift: None

$\begin{array}{c} x & f (x) \\ 0 & - \frac{1}{4} \\ \frac{π}{8} & 0 \\ \frac{π}{4} & \frac{1}{4} \\ \frac{3 π}{8} & 0 \\ \frac{π}{2} & - \frac{1}{4} \end{array}$

Step 8

Graph y=-1/4cos(4x)

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