Graph y=(1^x)/2

$y = \frac{1^{x}}{2}$

Step 1

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 0$

$b = \frac{1}{2}$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $0$

y-intercept: $(0, \frac{1}{2})$

Slope: $0$

y-intercept: $(0, \frac{1}{2})$

Step 2

Find two points on the line.

$\begin{array}{c} x & y \\ 0 & \frac{1}{2} \\ 1 & \frac{1}{2} \end{array}$

Step 3

Graph the line using the slope, y-intercept, and two points.

Slope: $0$

y-intercept: $(0, \frac{1}{2})$

$\begin{array}{c} x & y \\ 0 & \frac{1}{2} \\ 1 & \frac{1}{2} \end{array}$

Step 4