Graph y=11/8x^3

$y = \frac{11}{8} x^{3}$

Step 1

Find the point at $x = - 2$ .

Replace the variable $x$ with $- 2$ in the expression.

$f (- 2) = \frac{11 {(- 2)}^{3}}{8}$

Simplify the result.

Raise $- 2$ to the power of $3$ .

$f (- 2) = \frac{11 \cdot - 8}{8}$

Multiply $11$ by $- 8$ .

$f (- 2) = \frac{- 88}{8}$

Divide $- 88$ by $8$ .

$f (- 2) = - 11$

The final answer is $- 11$ .

$- 11$

Convert $- 11$ to decimal.

$y = - 11$

Step 2

Find the point at $x = 0$ .

Replace the variable $x$ with $0$ in the expression.

$f (0) = \frac{11 {(0)}^{3}}{8}$

Simplify the result.

Raising $0$ to any positive power yields $0$ .

$f (0) = \frac{11 \cdot 0}{8}$

Multiply $11$ by $0$ .

$f (0) = \frac{0}{8}$

Divide $0$ by $8$ .

$f (0) = 0$

The final answer is $0$ .

$0$

Convert $0$ to decimal.

$y = 0$

Step 3

Find the point at $x = 2$ .

Replace the variable $x$ with $2$ in the expression.

$f (2) = \frac{11 {(2)}^{3}}{8}$

Simplify the result.

Raise $2$ to the power of $3$ .

$f (2) = \frac{11 \cdot 8}{8}$

Multiply $11$ by $8$ .

$f (2) = \frac{88}{8}$

Divide $88$ by $8$ .

$f (2) = 11$

The final answer is $11$ .

$11$

Convert $11$ to decimal.

$y = 11$

Step 4

Find the point at $x = - 1$ .

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = \frac{11 {(- 1)}^{3}}{8}$

Simplify the result.

Raise $- 1$ to the power of $3$ .

$f (- 1) = \frac{11 \cdot - 1}{8}$

Multiply $11$ by $- 1$ .

$f (- 1) = \frac{- 11}{8}$

Move the negative in front of the fraction.

$f (- 1) = - \frac{11}{8}$

The final answer is $- \frac{11}{8}$ .

$- \frac{11}{8}$

Convert $- \frac{11}{8}$ to decimal.

$y = - 1.375$

Step 5

Find the point at $x = 1$ .

Replace the variable $x$ with $1$ in the expression.

$f (1) = \frac{11 {(1)}^{3}}{8}$

Simplify the result.

One to any power is one.

$f (1) = \frac{11 \cdot 1}{8}$

Multiply $11$ by $1$ .

$f (1) = \frac{11}{8}$

The final answer is $\frac{11}{8}$ .

$\frac{11}{8}$

Convert $\frac{11}{8}$ to decimal.

$y = 1.375$

Step 6

The cubic function can be graphed using the function behavior and the points.

$\begin{array}{c} x & y \\ - 2 & - 11 \\ - 1 & - 1.375 \\ 0 & 0 \\ 1 & 1.375 \\ 2 & 11 \end{array}$

Step 7

The cubic function can be graphed using the function behavior and the selected points.

Falls to the left and rises to the right

$\begin{array}{c} x & y \\ - 2 & - 11 \\ - 1 & - 1.375 \\ 0 & 0 \\ 1 & 1.375 \\ 2 & 11 \end{array}$

Step 8

Graph y=11/8x^3

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